force on femur
By what amount does the 52 cm long femur of an 67 kg runner compress at this moment? The cross-section area of the bone of the femur can be taken as 5.2X10^-4 m^2.
Homework Answers
Quite simple actually
F=Y*A/L*ΔL
We can rewrite it like this.
ΔL=F*L/Y/A
F=67kg*9.8m/s2
L=.52m
A=5.2*10-4
Y=1.6*1010
Since the force in multiplied by 3x when the foot hits the ground we multiply the force x3.
F=67kg*9.8m/s2*3
ΔL=(67kg*9.8m/s2*3)*.52/(1.6*1010)/(5.2*10-4)=0.00012 m
change to cm = 0.012 cm
The normal force of the ground on the foot can reach three times a runner's body...
The normal force of the ground on the foot can reach three times a runner's body weight when the foot strikes the pavement. Part A By what amount does the 52-cm-long femur of an 85 kg runner compress at this moment? The cross-section area of the bone of the femur can be taken as 5.2×10−4m2 and its Young's modulus is 1.6×1010N/m2. Express your answer to two significant figures and include the appropriate units.
By what amount does the 52-cm-long femur of an 73 kg runner compress at this moment? The cross-section area of the bone...
By what amount does the 52-cm-long femur of an 73 kg runner compress at this moment? The cross-section area of the bone of the femur can be taken as 5.2×10?4m2 and its Young's modulus is 1.6×1010N/m2.
The femur bone in the human leg has a minimum effective cross section of about 3.0...
The femur bone in the human leg has a minimum effective cross section of about 3.0 cm^2 (3.0 times 10^-4 m2). Compressive strength for bone is 170 times 10^6 N/m^2. Part A How much compressive force can it withstand before breaking?
Running on a treadmill is slightly easier than running outside because there is no drag force...
Running on a treadmill is slightly easier than running outside because there is no drag force to work against. Suppose a 60 kg runner completes a 5.0 km race in 23 minutes. the drag force on the runner during the race is 6.8 N when the cross section area is .72m^3. Part B What is this force as a fraction of the runner's weight?
How much does the femur shorten when a 70-kg person stands on one foot? Assume that...
How much does the femur shorten when a 70-kg person stands on one foot? Assume that in the absence of stress, the femur has a length of 0.5 m. The femur’s cross-sectional area can be modeled as a hollow circular tube with internal diameter d1 = 2.5 cm and external diameter d2 = 3.3 cm. Young’s modulus for bone compression is 9 × 109 N/m2.
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles t...
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alternately stretches, as you bring your weight down onto your forward foot, and contracts to push you off the ground. A 70 kg runner has an Achilles tendon that is 15 cm long and has a cross-section area of 110 mm2 typical values for a person of this size. Part A By how much will the runner's Achilles...
Running on a treadmill is slightly easier than running outside because there is no drag force...
Running on a treadmill is slightly easier than running outside because there is no drag force to work against. Suppose a 60 kg runner completes a 5.0 km race in 16 minutes. A) Determine the drag force on the runner during the race. Suppose that the cross section area of the runner is 0.72 m2. Express your answer with the appropriate units. D = ___ (value) ______ (units) B) What is this force as a fraction of the runner's weight?...
Due to its highly mechanical function, there is a tendency for people to think of bone as being i...
can you solve this please ?
Due to its highly mechanical function, there is a tendency for people to think of bone as being inert or less biologically active than the soft tissues of the body. In fact, bone is a highly dynamic tissue that is constantly in a state of remodeling. Bone adapts its structure in response to the loads that it experiences, as described by Wolffs law. Remodeling of bone microstructure is a cell- driven process that occurs...
QUESTION 4 a) The human femur bone breaks if compressive stress greater than 1.50 * 10...
QUESTION 4 a) The human femur bone breaks if compressive stress greater than 1.50 * 10 N/m2 is imposed on it. Assuming the Young's modulus for bone is 1.50 * 1010 N/m2, determine 1) the maximum force that can be exerted on the femur bone in the leg if it has a cross-sectional area of 4.90 x 10-4 m2 by how much does a 0.400 m long bone shorten if this maximum force is applied compressively to the bone. (6...
When you walk and your heel strikes the ground, there is a total force from the...
When you walk and your heel strikes the ground, there is a total
force from the ground (a vector sum of the friction force and the
normal force) that is directed along your leg. For a regular gait,
the leg is at a 25° angle, and the normal force peaks at 1.1 times
the body weight. Assume the person has a mass of 50 kg.
A) For a normal gait, compute the magnitude of the normal force,
the magnitude of...
The femur bone in the human leg has a minimum effective cross section of about 3.0 cm^2 (3.0 times 10^-4 m2). Compressive strength for bone is 170 times 10^6 N/m^2. Part A How much compressive force can it withstand before breaking?
can you solve this please ?
Due to its highly mechanical function, there is a tendency for people to think of bone as being inert or less biologically active than the soft tissues of the body. In fact, bone is a highly dynamic tissue that is constantly in a state of remodeling. Bone adapts its structure in response to the loads that it experiences, as described by Wolffs law. Remodeling of bone microstructure is a cell- driven process that occurs...
QUESTION 4 a) The human femur bone breaks if compressive stress greater than 1.50 * 10 N/m2 is imposed on it. Assuming the Young's modulus for bone is 1.50 * 1010 N/m2, determine 1) the maximum force that can be exerted on the femur bone in the leg if it has a cross-sectional area of 4.90 x 10-4 m2 by how much does a 0.400 m long bone shorten if this maximum force is applied compressively to the bone. (6...
When you walk and your heel strikes the ground, there is a total
force from the ground (a vector sum of the friction force and the
normal force) that is directed along your leg. For a regular gait,
the leg is at a 25° angle, and the normal force peaks at 1.1 times
the body weight. Assume the person has a mass of 50 kg.
A) For a normal gait, compute the magnitude of the normal force,
the magnitude of...
Most questions answered within 3 hours.
-
Calculate the pH of each of the following solutions.
0.50 M HBr
3.1×10−4 M KOH
4.2×10−5...
asked 3 hours ago -
For the year ended December 31, Depot Max’s cost of merchandise
sold was $85,600. Inventory at the...
asked 3 hours ago -
Week 10 - Professional Memo Assignment
Professional Memo Assignment
Your mission for this week, should you...
asked 3 hours ago -
Write a Python program that stores the data for each
player on the team, and it...
asked 3 hours ago -
In
the last 3 months, mike never knows when he is going to get his
allowance...
asked 4 hours ago -
Is Ca(OH)2 a Bronsted base, Lewis base, or both? Why?
asked 3 hours ago -
1A- Why don’t voters complain about U.S. tariffs on imported
sugar?
Because sugar is only a...
asked 4 hours ago -
Cash Payback Period
Primera Banco is evaluating two capital investment proposals for
a drive-up ATM kiosk,...
asked 4 hours ago -
Create a button in Swift (Xcode) that will create a charge,
create a charge using Stripe's...
asked 4 hours ago -
The reaction rate of CO and NO2 in the reaction
CO(g) + NO2(g) → CO2(g) +...
asked 4 hours ago -
Imagine that a chemist puts 6.40 mol each of
C3H8 and O2 in a 1.00-L container...
asked 4 hours ago -
How much money should be invested today in order to have $8340
at the end of...
asked 4 hours ago