When you walk and your heel strikes the ground, there is a total force from the...
When you walk and your heel strikes the ground, there is a total force from the ground (a vector sum of the friction force and the normal force) that is directed along your leg. For a regular gait, the leg is at a 25° angle, and the normal force peaks at 1.1 times the body weight. Assume the person has a mass of 50 kg.
A) For a normal gait, compute the magnitude of the normal force, the magnitude of the friction force, and the minimum possible coefficient of friction.
B)If you are walking on a slippery surface, you take smaller strides. Given the cal- culation you have just completed, explain why this makes sense.
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When you walk and your heel strikes the ground, there is a total
force from the...
As you walk, the upper part of your body moves up and down with approximately simple harmonic motion. The smaller the amplitude of this motion the smaller the force you put on your joints and, of course, the more graceful is your walk. If you managed to
As you walk, the upper part of your body moves up and down with approximately simple harmonic motion. The smaller the amplitude of this motion the smaller the force you put on your joints and, of course, the more graceful is your walk. If you managed to develop your walk so that you have kept the amplitude down to 1.60 cm, what is the maximum acceleration of your body, in units of g = 9.80 m/s2, when you are walking at your...
Consider the ladder in 8.15. Compute the normal force again, assuming a 75 kg man is...
Consider the ladder in 8.15. Compute the normal force again,
assuming a 75 kg man is standing on the ladder (a) at its midpoint
and (b) four fifths of the way up the latter.
I posted this question earlier but was very confused on how it
was answered and laid out. I am not understanding how to go about
this or what formulas to use.
I know the answers is (a) 130.95 N and (b) 194.2 N but I do...
Consider the ladder in 8.15. Compute the normal force again,
assuming a 75 kg man is standing on the ladder (a) at its midpoint
and (b) four fifths of the way up the latter.
I posted this question earlier but was very confused on how it
was answered and laid out. I am not understanding how to go about
this or what formulas to use.
I know the answers is (a) 130.95 N and (b) 194.2 N but I do...
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