Question

a steady horizontal force lasting for 2.10 s gives a 1.25 kg object an acceleration of 3.20

a steady horizontal force lasting for 2.10 s gives a 1.25 kg object an acceleration of 3.20 m/s^2 on a frictionless table. what impulse does this force give to theobject?
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Answer #1

We know that impulse
J = F * t
= m * a * t
= 1.25 * 3.20 * 2.10
= 8.4 N-s
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