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When solid Ca(CH3COO)2 is dissolved in a nearly saturated solution of Ca(CH3COO)2 the solution...

When solid Ca(CH3COO)2 is dissolved in a nearly saturated solution of Ca(CH3COO)2 the solution becomes warmer. This information indicates that if the temperature of asolution is decreased,

a. delta H will become zero
b. the solubility of Ca(CH3COO)2 will increase
c. delta H will become negative
d. the solubility of Ca(CH3COO)2 will decrease
e. the solubility of Ca(CH3COO)2 will not change
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The answer is b. The solubility of Ca(CH3COO)2 will increase.


Since the solution becomes hot when Ca(CH3COO)2 is dissolved, the dissolution is exothermic, and the heat is released together with the dissolved ions:


Ca (CH3COO) 2 (s) == Ca2 + (aqueous solution) + 2 CH3COO- (aqueous solution) + heat


According to Le Chatelier's principle, lowering the temperature can eliminate heat and shift the balance to the right.


Therefore, the reaction will proceed in the forward direction, and more Ca(CH3COO) 2 will be dissolved, resulting in an increase in solubility.


answered by: Gavin
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