Question

Please explain every part, especially the equilibrium shifts

6. When a saturated solution of LiCI was chilled some solid solute formed. Answer parts a. - d (12) LiCl (s) Li+ (aq) + Cl. (aq) → a. The stress placed on the system was (an increase / a decrease) in temperature. b. The system's response was an attempt to (increase / decrease) the temperature. c. As a result the equilibrium shifted to the (right/ left) and the solubility of LiCI (increased d. At the lower temperature the solution of LiCI was decreased) 1. 4. unsaturated not enough information given 2. saturated 3. supersaturated

Answer 1

a.

When a saturated solution of LiCl was cooled (that is temperature is lowered). The stress placed on the system was a decrease in temperature.

b.

When a saturated solution of LiCl was cooled (that is temperature is lowered), the equilibirium will shift to increase in temperature.

The system’s response was an attempt to increase the temperature.

c.

LiCl(s)     =     Li+(aq)     +     Cl-(aq)

When a saturated solution of LiCl was cooled (that is temperature is lowered), some LiCl in the form of solid has precipitated out (which is in the left side of the equilibirium).

So, the equilibrium will shift to the right. In right of the equilibirium the solubility of LiCl increased.

Again, with more explanation;

Since some LiCl is precipitate out, so, more LiCl solid can dissolve in the solution and hence the solubility will increase.

Answers are

right

increased

d.

At the lower temperature the solution of LiCl was unsaturated, since some of the LiCl solid has precipitated out of the solution.