Question

The 20.0cm by 35cm rectangular circuit shown in the figure ishinged along side ab. it carries a clockwise 5.00 A current and islocated in a uniform 1.20T magneticfield oriented perpendicular totwo of its sides, as shown.Which force exerts a torque about the hinge ab?calculate only the force that exerts the torque mentioned inpart A.use your results from part B to calculate the torque that themagnetic field exerts on the circuit about the hinge axis ab.

Answer 1

a)Given thatLength (a) = 35.0cm= 0.350mBreadth (b) = 20.0cm= 0.20mCurrent (I) passing through the circuit = 5.0AMagnetic field strength(B) = 1.20TThen the force exerts a torque about the hinge ab isF = BIasin90^o= (1.20T)(5.0A)(0.350m)b)And then torque torque that the magnetic field exerts on thecircuit about the hinge axis ab isτ= (perpendicular distance)(F)= (0.20m)(1.20T)(5.0A)(0.350m)Do the calculation work.