Question

calculate the mass in grams of iodine that will react compeltely with 20.4g of aluminum to form aluminum iodide

Answer 1

;

288 g (3sf)

Explanation;

The balanced equation for the formation of aluminium iodide is:

3I + Al --> AlI₃

as

moles(mol) = mass(g) / Mr (g mol^-1)

Mr(g mol^-1) of Al =26.9815

Mass (g) of Al = 20.4

∴ moles (mol) = 20.4 g / 26.9815g mol^-1

= 0.75607

As 1 moles of Al reacts with 3 moles of I

∴ moles of I = 2.268 (4sf)

as

moles(mol) = mass(g) / Mr (g mol^-1)

∴ mass (g) of I =2.268 mol X126.90g mol^-1

= 287.8 g (4sf)

Hope this Helps!