Question

What is the half-life of this isotope?

If 12% of a certain radioisotope decays in 5.2 years, what isthe half-life of this isotope?A. 0.59 yrB. 1.7 yrC. 22 yrD. 28 yrE. 32 yr
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Answer #1
First u have to use the formulaln[A]t / [A]0 = -ktLet the initial concentration of radioisotope is x then 12% ofx decays which means 88% remains[A] t = 88% of x = 0.88x[A]0 = xk = ?t = 5.2yrsby this equation , find the value of k, after that ucalculate the value of t1/2k = 0.693 / t1/2Hope thishelps!
answered by: Rose7
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