B is the coefficient matrix = 1 4 1 2
0 1 3 -4
0 2 6 7
2 9 5 -7
The part of the question that confuses me is the part that asks if the columns of B span R3 or not because I am only sure of R4.
AT THE OUT SET PLEASE NOTE THE FOLLOWING
BASIS
TO FORM A BASIS FOR RN , WE NEED
1.WE NEED A SET OF N AND ONLY N VECTORS
2.THEY SHALL BE L.I.
TO SPAN RN ...
1.WE NEED A SET OF N OR MORE VECTORS
2.ANY N VECTORS IN THE SET SHALL BE L.I.
SO NOW WE HAVE R4..THAT IS N=4
SO WE NEED AT LEAST 4 VECTORS TO SPAN R4..WE HAVE 4 VECTORS ...OK..
NOW WE HAVE TO CHECK WHETHER THEY ARE L.I.
B= | ||||||||
1 | 4 | 1 | 2 | |||||
0 | 1 | 3 | -4 | |||||
0 | 2 | 6 | 7 | |||||
2 | 9 | 5 | -7 | |||||
NR4=R4-2R1 | ||||||||
1 | 4 | 1 | 2 | |||||
0 | 1 | 3 | -4 | |||||
0 | 2 | 6 | 7 | |||||
0 | 1 | 3 | -11 | |||||
NR1=R1-4R2…NR3=R3-2R2…NR4=R4-R2 | ||||||||
1 | 0 | -11 | 18 | |||||
0 | 1 | 3 | -4 | |||||
0 | 0 | 0 | 15 | |||||
0 | 0 | 0 | -7 | |||||
WE FIND COLUMNS 1,2,3 ARE L.D. | ||||||||
AS THEY HAVE ZEROS IN THE III AND IV COORDINATES. | ||||||||
HENCE THEY CAN NOT SPAN R4…………ANSWER | ||||||||
THUS WE HAVE ONLY 3 INDEPENDENT COLUMN VECTORS | ||||||||
SAY COLUMNS.1,2 AND 4 | ||||||||
NOW LET US CHECK WHETHER THEY SPAN R3… | ||||||||
WE HAVE 4 VECTORS .. | ||||||||
THAT IS MORE THAN 3 NEEDED TO SPAN R3….OK | ||||||||
3 OF THEM ARE L.I. ….OK | ||||||||
SO THEY SPAN R3 …ANSWER | ||||||||
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matrix A and I believe the answer is W = span{ v1 u2 u3 } however
I'm not really sure if that is correct or not. Please give a small
explanation. Also im not sure if I need to represent the vectors in
A as columns or rows, or if either one works.
For the next two problems, W is the subspace of R4 given by...