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Help!! Proton at center of a triangle potential energy problem

Three electrons form an equilateral triangle .600 nm on each side. A proton is at the center of the triangle.

What is the potential energy of this group of charges? (answer in Joules)
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Answer #1
potential energy = U = kq1q2/r

q = 1.6*10^-19 C
r = 0.6*10^-9 m

U = Uab + Ubc + Uca

= 3 Uab = 3kq^2/r

= 3*9*10^9*(1.6*10^-19)^2/0.6*10^-9

= 115.2*10^-20 J --> ans
answered by: endrew
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