Element X has two isotopes: X - 100 and X 104. If the atomic mass of X is 101 amu, what is the relative abundance of each isotope in nature?
let a = % abundance x-100
let b = % abundance x-104
a + b = 100
a = 100 - b
101 = ( 100-b) + 104 b / 100
10100 = 10000 - 100 b + 104 b
100 = 4 b
b = 25 %
a = 75 %
the element X has naturally occurring isotope. The masses (amu) and % abundance of the isotopes are given below. the average atomic mass of the element is ? Isotope: 221X, 220X, 218 X Abundance: 74.22, 12.78, 13.00 Mass: 220.9, 220.0, 218.1
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