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Mastering Physics ± PSS 30.1: Inductors in Circuits

Learning Goal: To practice Problem-Solving Strategy 30.1: Inductors in Circuits.

A circuit has a 3.9 V battery connected inseries with a switch. When the switch is closed, the battery powers two paths in parallel, one of which has a resistor of resistance R1 = 90 Omega in series with an inductor of inductance L = 1.3×10−2 H, while the other has a resistor of resistance R2 = 430 Omega. What is the current supplied by the battery at a time t = 0.3 ms after the switch is closed?

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Answer #1

From Kirchhoffs loop rule to the left closed loop, 3.9 V-izR2 0 3.9 V 3-430 Ω 0.009 A The time constant is, 1.3x102 H 90 Ω -

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