Use the data in the table below to calculate Cp, Cpl, Cpu, and Cpk, assuming that the specifications are 3.75 ± 1.26. Do not round intermediate calculations. Round your answers to three decimal places.
Cp: Cpl: Cpu: Cpk: Construct the frequency distribution for the data. For calculating the cell width assume 8 cells, the lower limit of 2.49 inches and upper limit of 5.01 inches. If your answer is zero, enter "0". Round your answers for interval boundaries to three decimal places and round your answers for frequencies to the nearest whole number.
Choose the correct histogram for the data. The correct histogram is _______ .
|
Given details
Upper specification limit = 3.75
Lower specification limit = 1.26
Step 1:
Calculate Average(X-bar) and standard deviation for the given sample data.
Table 1 - average of X-bar and standard deviation
Step 2:
Calculate Cp, Cpl, Cpu, and Cpk
= Min ( 0.107,0.299) = 0.107
Step3:
Given lower limit = 2.49 and upper limit = 5.01
Steps to construct frequency distribution table
The result of frequency table and relevant graph is shown below
Table 2 - frequency table
Therefore, the correct answer is D.
Use the data in the table below to calculate Cp, Cpl, Cpu, and Cpk, assuming that the specificati...
The median wage for economics degree holders is determined by the following equation: log( wage) = Be + B educ + B, exper+ B temure + B.age+ B married + u where educ is the level of education measured in years, exper is the job-market experience in years, tenure is the time spend with the current company in years, age is the age in years and married is a dummy variable indicating if a person is married. 935 reg Iwage...
REGRESSION 2 • reg bught cigs faminc male Source SS df MS = = Model Residual 20477.12 554134.6 3 6825.70666 1,384 400.386272 Number of obs F(3, 1384) Prob > R-squared Adj R-squared Root MSE 1,388 17.05 0.0000 0.0356 0.0335 20.01 - Total 574611.72 1,387 414.283864 bwght Coef. Std. Err. Piti (95Conf. Intervall cigs famine male _cons -.4610457 0913378 .09687980291453 3.113968 1.076396 115.2277 1.20788 -5.050.000 3.32 0.001 2.89 0.004 95.400.000 -.6402212 .0397062 1.002423 112.8582 - 2818702 .1540535 5.225513 117.5972 f) Conduct...
1. Two manufacturing processes are being compared to try to reduce the number of defective products made. During 8 shifts for each process, the following results were observed: Line A Line B n 181 | 187 Based on a 5% significance level, did line B have a larger average than line A? *Use the tables I gave you in the handouts for the critical values *Use the appropriate test statistic value, NOT the p-value method *Use and show the 5...
Write the C program, to achieve as shown in the sample code execution, using the given struct and using the comments in the given main program below: typedef struct{ char first[20]; char last[20]; float gpa; int score; } student; int main(void){ student *ptr; //first name //last name //student gpa //student score } //ask a user to enter the number of students, num //dynamically allocate memory for an array of students of the appropriate size (i.e. //num that the user just...
ample Data Item 1 2 3 4 5 Group 1 Group 2 Group 3 13 19 16 13 18 14 13 19 16 13 19 15 12 18 15 Print Done p=0.95 D 2 4 5 6 7 8 9 10 D 2 4 5 6 7 8 9 10 11 12 1797 6.08 4.50 3.93 3.64 3.46 3.34 3.26 3.20 3.15 3.11 3.08 3.06 3.03 3.01 3.00 2.98 2.97 2.96 2.95 2.92 2.89 2.86 2.83 2.80 2.77 13 14...
The subjects in the data are college students. In the data, id is student ID, anxiety is student’s anxiety score via Anxiety Scale, selfest is student’s self-esteem score via Rosenberg Self-esteem Scale, GPA is student’s GPA; for gender, 0=female, 1=male; for grade, 1=freshman, 2=junior, 3=senior. We have known that population mean for Anxiety Scale is μ=60 with σ=10. Raise relevant questions ( 2 questions is fine) about the data extensively, the questions can be either about descriptive analysis or inferential...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Suppose 1000 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. Exactly 495 heads Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. The probability of getting exactly 495...
Suppose 16 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. More than 11 tails. Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. Binomial probability = (Round to...