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Problem 3 (23%) The following beam is discretize into 2 elements. E-29x106 psi, I-375 in and A (b...
2. The beam shown in the figure below is a wide-flange W16x31 with a cross-sectional area...
2. The beam shown in the figure below is a wide-flange W16x31 with a cross-sectional area of 9.12 in- and a depth of 15.88 in. The second moment of area is 375 in". The beam is subjected to a uniformly distributed load of 1000 lb/ft and a point load of 500 lb. The modulus of elasticity of the beam is E = 29x106 1b/in. Determine the vertical displacement at node 3 and the rotations at nodes 2 and 3. Also,...
t is given that E 29.5 x 10 psi and 3- Consider the four-bar truss shown...
t is given that E 29.5 x 10 psi and 3- Consider the four-bar truss shown in the figure below Ae 1 in2 for all elements (a) Determine the element stiffness matrix for each element. (b) Assemble the global stiffhness matrix for the entire truss. (c) Using the elimination approach, solve for the nodal displacement. (d) Calculate the reaction forces (25 points) 25000 lb 4 4 30 in. 2 20000 lb _40 in.
Problem3 The following problem is intended to be solved by hand. For the structure shown below A.) Label the structure degrees of freedom (free only) and number the elements B.) For each element, det...
Problem3 The following problem is intended to be solved by hand. For the structure shown below A.) Label the structure degrees of freedom (free only) and number the elements B.) For each element, determine the stiffness matrix in global element coordinates. Label each row and column of each element matrix with its corresponding global DoF. C.) Assemble the structure stiffness matrix Kfr from the element global stiffness matrices D.) Calculate the deflection of the free DoFs. 5 ft 500 k...
Solve the following truss problem. All truss members are ANSI 2x2x0.25 hollow square tubes (with rounded...
Solve the following truss problem. All truss members are ANSI 2x2x0.25 hollow square tubes (with rounded corners) for which the cross-section area is A-1.5891 in2. The material has a modulus of E-29E6 psi. Length of element 1 and 5 is L-20 inches, and length of element 3 and 6 is 2L 40 inches. 7 5 6 P-1000 lb 2. 1. Solve in an Excel spreadsheet using the truss element. Note that there are only four different element stiffness matrices (look...
3) For the beam and loading shown in figure, E = 30 x 106 psi, I...
3) For the beam and loading shown in figure, E = 30 x 106 psi, I = 200 int. Determine (a) the reaction force at A and (b) the deflection at C. 3 ft 8 kip 2 kip/ft IA с в | -8 ft
3) For the beam and loading shown in figure, E = 30 x 106 psi, i...
3) For the beam and loading shown in figure, E = 30 x 106 psi, i = 200 inº. Determine (a) the reaction force at A and (b) the deflection at C. 3 ft 8 kip 2 kip/ft IA с B -8 ft
3) For the beam and loading shown in figure, E = 30 x 106 psi, I...
3) For the beam and loading shown in figure, E = 30 x 106 psi, I = 200 in. Determine (a) the reaction force at A and (b) the deflection at C. 3 ft 8 kip 2 kipit IA с В | -8 ft
Problem 5.102: Solve the structure composed of 2 beam and 3 truss elements by taking advantages...
Problem 5.102: Solve the structure composed of 2 beam and 3 truss elements by taking advantages of the symmetry of structure. (1) Show your half model with proper boundary conditions; (2) How many free DOFs are there in your model? (3) Assemble and show the reduced global stiffness matrix and load vector in your model; and (4) Compute the displacements at Node 2, and element stress in Truss 4 or 5 by following Element and Node IDs as defined in...
2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Young's modulus E(GPa) is the same for...
2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Young's modulus E(GPa) is the same for the three truss vertical downward force P(kN) is a members. The cross sectional area of each of the truss members is indicated below and expressed in terms of a constant A. By using the stiffness method: (a) Compute the reduced stiffness matrix Kg [5 marks [10 marks (b) Calculate the global displacements of node 4 in terms of P,...
Problem 2 (3 points) 1m 1m For the planar truss below, determine the nodal oay displacements in t...
Problem 2 (3 points) 1m 1m For the planar truss below, determine the nodal oay displacements in the Global Coordinate system using the finite element direct method Global y Node 2 Node 1 Global x Element 1Element 2 2m Assume all the truss members are of the same Young's modulus E-65x 109 Nm. Element 1 and element 2 have the same cross-sectional area of 0.01 m and the cross-sectional area of element 3 is 0.02 m2. Do not rename the...
2. The beam shown in the figure below is a wide-flange W16x31 with a cross-sectional area of 9.12 in- and a depth of 15.88 in. The second moment of area is 375 in". The beam is subjected to a uniformly distributed load of 1000 lb/ft and a point load of 500 lb. The modulus of elasticity of the beam is E = 29x106 1b/in. Determine the vertical displacement at node 3 and the rotations at nodes 2 and 3. Also,...
t is given that E 29.5 x 10 psi and 3- Consider the four-bar truss shown in the figure below Ae 1 in2 for all elements (a) Determine the element stiffness matrix for each element. (b) Assemble the global stiffhness matrix for the entire truss. (c) Using the elimination approach, solve for the nodal displacement. (d) Calculate the reaction forces (25 points) 25000 lb 4 4 30 in. 2 20000 lb _40 in.
Problem3 The following problem is intended to be solved by hand. For the structure shown below A.) Label the structure degrees of freedom (free only) and number the elements B.) For each element, determine the stiffness matrix in global element coordinates. Label each row and column of each element matrix with its corresponding global DoF. C.) Assemble the structure stiffness matrix Kfr from the element global stiffness matrices D.) Calculate the deflection of the free DoFs. 5 ft 500 k...
Solve the following truss problem. All truss members are ANSI 2x2x0.25 hollow square tubes (with rounded corners) for which the cross-section area is A-1.5891 in2. The material has a modulus of E-29E6 psi. Length of element 1 and 5 is L-20 inches, and length of element 3 and 6 is 2L 40 inches. 7 5 6 P-1000 lb 2. 1. Solve in an Excel spreadsheet using the truss element. Note that there are only four different element stiffness matrices (look...
3) For the beam and loading shown in figure, E = 30 x 106 psi, I = 200 int. Determine (a) the reaction force at A and (b) the deflection at C. 3 ft 8 kip 2 kip/ft IA с в | -8 ft
3) For the beam and loading shown in figure, E = 30 x 106 psi, i = 200 inº. Determine (a) the reaction force at A and (b) the deflection at C. 3 ft 8 kip 2 kip/ft IA с B -8 ft
3) For the beam and loading shown in figure, E = 30 x 106 psi, I = 200 in. Determine (a) the reaction force at A and (b) the deflection at C. 3 ft 8 kip 2 kipit IA с В | -8 ft
Problem 5.102: Solve the structure composed of 2 beam and 3 truss elements by taking advantages of the symmetry of structure. (1) Show your half model with proper boundary conditions; (2) How many free DOFs are there in your model? (3) Assemble and show the reduced global stiffness matrix and load vector in your model; and (4) Compute the displacements at Node 2, and element stress in Truss 4 or 5 by following Element and Node IDs as defined in...
2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Young's modulus E(GPa) is the same for the three truss vertical downward force P(kN) is a members. The cross sectional area of each of the truss members is indicated below and expressed in terms of a constant A. By using the stiffness method: (a) Compute the reduced stiffness matrix Kg [5 marks [10 marks (b) Calculate the global displacements of node 4 in terms of P,...
Problem 2 (3 points) 1m 1m For the planar truss below, determine the nodal oay displacements in the Global Coordinate system using the finite element direct method Global y Node 2 Node 1 Global x Element 1Element 2 2m Assume all the truss members are of the same Young's modulus E-65x 109 Nm. Element 1 and element 2 have the same cross-sectional area of 0.01 m and the cross-sectional area of element 3 is 0.02 m2. Do not rename the...
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