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As we considered in the class conjugation is generally more effective in the para position than m...

As we considered in the class conjugation is generally more effective in the para position than meta. Consider two electron-donating groups: -NH2 and -OCH3. For -OCH3 group spara and smeta values are to -0.29 and 0.11, respectively. For amino group, however, spara = -0.62 and smeta = 0.00. Explain the following observations below. Draw the structures to support your answer.

a) Why is smeta value more positive than spara? b) How would you explain smeta = 0.00 for -NH2 group?

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1 20 1.5ス 0나 aned neta positi。 smeta = 0.00 3 0

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