For 0 and 90 degree,
,
Mid-plane strain = 0;
,
weight of moisture absorption per unit weight of the lamina.
......................................Eq(1)
where,
where,
,
,
or,
Substituting the values of N , B in Eq. (1) we can get the value
of vector k ,
11E E1140 x 109 -1 = 7.142 × 10-12Pa-1,S22 = -1 = 1 × 10-10Pa-1,S12 = 10× 109Pa -2.42x 10-12Pa-1,S66 El - 140x109 Pa- Pa-1-1.66× 10-10Pa-1 - 92би 109 G12
S2 1SIS22 - Si2 12 S1192-ול2 Q12- 2 e11 Q2 Q66 So6
10-10 Q11-10-10×7.142× 10-12- (2.42 x 10 12)2 Pa = 0.1417 x 1012 Pa
7.142 x 10-12 10 Pa = 1.008×1010Pa 22 = x 7.142 x 10-12-(2.42 x 10-12)2
Q12 1010Pa 2.42 x 10-12 10-10 x 7.142x 10-12- (2.42x 10-12)2 P: 0.3416
Q66-G12-6 x 109Pa
Q11 Q12 0 2 2 2 2 0 0 66 3
Q22 Q12 0 Q90=Q12 Q11 0 2 0 0 66 3
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AT-180- 30 150°
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01 0
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