Change this program in assembly language to loop until it encounters a sentinel value, which is a negative number. The data begins at x3100. Use only one branch command. There will always be at least one positive integer in the list.
.ORIG x3000
LEA R1, xFF
AND R3, R3, #0
AND R2, R2, #0
ADD R2, R2, #12
BRz #5
LDR R4, R1, #0
ADD R3, R3, R4
ADD R1, R1, #1
ADD R2, R2, #-1
BRnzp #-6
.END
.ORIG x3000
LEA R1, xFF
AND R3, R3, #0
AND R2, R2, #0
ADD R2, R2, #12
LDR R4, R1, #0
ADD R3, R3, R4
ADD R1, R1, #1
ADD R2, R2, #-1
BRnzp #-6
.END
Change this program in assembly language to loop until it encounters a sentinel value, which is a...
I am writing a code for the LC3 Simulator. This is in assembly, I need assistance with the numbers 5-8. Thank you. ALU OPERATIONS 1. Compute the sum X +Y and place it at location x3102. 2. Compute X AND Y and place it at location x3103. 3. Compute X OR Y and place it at location x3104. 4. Compute NOT(X) and place it at location x3105. 5. Compute NOT(Y) and place it at location x3106. 6. Compute X +3...
Part 2 (22 pts) .ORIG x3000 LEA R1, STRZ AND R2, R2, #0 LD R4, CHAR REPEAT LDR R3, R1, #0 BRz FINISH ;Branch to FINISH if the value of R3 is zero ADD R3, R3, R4 BRnp PASS ;Branch to PASS if the value of R3 is positive or negative ADD R2, R2, #1 PASS ADD R1, R1, #1 BR REPEAT ;Branch always to REPEAT FINISH ST R2, COUNT HALT CHAR .FILL xFF91 COUNT .FILL x0000 STRZ .STRINGZ "Hello...
; original codes provided as following .ORIG x3000 ; begin at x3000 ; input two numbers IN ; input an integer character (ascii) {TRAP 23} LD R3, HEXN30 ; subtract x30 to get integer ADD R0, R0, R3 ADD R1, R0, x0 ; move the first integer to register 1 IN ; input another integer {TRAP 23} ADD R0, R0, R3 ; convert it to an integer ; add the numbers ADD R2, R0, R1 ; add the two integers...
Write a program in assembly language that loads register R2 with the word in memory location which is 10 bytes above the address in R0; and loads register R3 with the word in memory location which is 10 bytes below the address in R1. Your program must compare the two numbers in R2 and R3. If number in R2 is less than or equal to the number in R3 it must add the two numbers and save the result in...
Section B - ARM Assembly Language (25 marks) An ARM instruction set summary is provided at the end of this paper 1. (5 marks) Consider the following assembly instruction STMFD r13!, (r5-6} Before executing this instruction, registers hold the following values: Register Value Register r9 Value r4 0x00400040 0x00000000 r5 r10 0x11223344 0x00800080 r6 0x55667788 r11 0x10001000 r7 0x99aabbcc r12 0x20002000 r8 exddeeff00 r13 ex40004000 What memory locations are affected after executing the above instruction? In a table, with a...
13) (4 pts) Squaring a number is useful in many other algorithms. This assembly routine calculates the square of an unsigned integer. How long does this take in clock cycles (worst case). Assume ARM 32 bit instruction set and the integer is in R0 before we begin. AREA L.textl, CODE, READONLY PROC EXPORT square square MOV R1,RO; CMP R1, #0 ANDS R3,RO,R1 BNE skip ADD RO,R1, LSL R3; MOV R2,R2, LSL #1 CMP R2, #0 BNE loop BX LR loop...
A C program has been compiled into the Atmel AVR assembly language. The following instruction, which is located at address 0x002A, is executed: i.) What is the binary value contained in the instruction register (IR) when the instruction is executed? ii.) What is the hexadecimal value of the program counter (PC) when the instruction is executed? iii.) If register r1 = 0x40 and register r2 = 0x02 prior to executing the instruction, what are the contents of r1 and r2...
Language = Java Create a program to receive book prices until a sentinel value is entered. (Be sure to tell your user what the sentinel value is so they can type it to indicate they are finished with entering input.) After the sentinel value is entered, compute the total book order total and return the following to the user. As book prices are entered, you'll need to have some way to capture the number of books they ordered and the...
The classic five-stage pipeline MIPS architecture is used to execute the code fragments in this problem. Assume the followings: The architecture fully supports forwarding, Register write is done in the first half of the clock cycle; register read is performed in the second half of the clock cycle, Branches are resolved in the third stage of the pipeline and the architecture does not utilize any branch prediction mechanism, Register R4 is initially 100. L1: lw R1, 0(R4) add R3, R1, R2 sw ...