At 900 K, the reaction CO2 (g) + C (solid) = 2 CO (g) comes to equilibrium. For the standard stat...

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At 900 K, the reaction CO2 (g) + C (solid) = 2 CO (g) comes to equilibrium. For the standard stat...

At 900 K, the reaction
CO2 (g) + C (solid) = 2 CO (g)
comes to equilibrium. For the standard states shown above, and a standard state pressure of 1 atm for the gas phase, the equilibrium constant K = 0.178.

a. Determine the mole fraction of CO, yCO, at equilibrium at 10 atm assuming the gas phase is an ideal gas.

b. Suppose at this pressure, it is desired to not produce any solid

C. What is the maximum possible yCO where carbon will not form?

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Answer 1

Answer #1

a. Let concentration of CO = x

CO2 = 1-x

C = 1-x

a. x²/(1-x)² = 0.178

x << 1

x2 = 0.178

x = 0.42

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Answer 2

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At 900 K, the reaction CO2 (g) + C (solid) = 2 CO (g) comes to equilibrium. For the standard stat...

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At 900 K, the reaction CO2 (g) + C (solid) = 2 CO (g) comes to equilibrium. For the standard stat...

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At 900 K, the reaction CO2 (g) + C (solid) = 2 CO (g) comes to equilibrium. For the standard stat...