Question

in each reaction box place the best reagent and conditions from the list below. DEET

In each reaction box, place the best reagent and conditions from the list below. The first reagent is right, stuck beyond that one.

In each reaction box, place the best reagent and c

2 0
Add a comment Improve this question Transcribed image text
✔ Recommended Answer
Answer #1

General guidance

Concepts and reason

The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.

Here, the starting reactant is 1-bromo-3-methylbenzene and the final product is N,N-diethyl-3-methylbenzamide.

Fundamentals

Sodium amide (NaNH2{\\rm{NaN}}{{\\rm{H}}_2}) is used as base, which abstract the proton.

Mg in the presence of ether forms a Grignard reagent.

Carbon dioxide reacts with Grignard reagent followed by the hydrolysis gives carboxylic acid.

Thionyl chloride (SOCl2{\\rm{SOC}}{{\\rm{l}}_2}) converts the acid to acid chloride.

Step-by-step

Step 1 of 5

The reaction is as follows:

MgBrMg, ether1-bromo-3-methylbenzenem-tolylmagnesium bromide

Explanation | Hint for next step

Treatment of 1-bromo-3-methylbenzene with magnesium in the presence of ether gives m-tolylmagnesium bromide.

Step 2 of 5

The reaction is as follows:

MgBrCO2m-tolylmagnesium bromide3-methylbenzoate

Explanation | Common mistakes | Hint for next step

Treatment of Grignard reagent with carbon dioxide forms a carboxylate ion. Here, the Grignard reagent (nucleophile) attacks the electrophilic carbon atom of carbon dioxide and forms a new C-C bond by the cleavage of pi bond.

Step 3 of 5

The reaction is as follows:

\u043e\u043dH303-methylbenzoate3-methylbenzoic acid

Explanation | Hint for next step

The carboxylate ion is protonated with the aqueous acid and forms the carboxylic acid.

Step 4 of 5

The reaction is as follows:

\u043e\u043dCISOCI23-methylbenzoic acid3-methylbenzoyl chloride

Explanation | Hint for next step

Treatment of 3-methylbenzoic acid with thionyl chloride gives 3-methylbenzoyl chloride.

Step 5 of 5

The reaction is as follows:

CINH(CH2CH32, (2 equiv)3-methylbenzoyl chlorideN,N-diethyl-3-methylbenzamide

The best reagents for the conversion of 1-bromo-3-methylbenzene to N,N-diethyl-3-methylbenzamide is as follows:

1)2)Mg, etherCO23)4)5) NH(CH2CH3)2, (2 equiv.)H30SOCl2DEET (the active ingredientin over the counter insectrepella


Treatment of 3-methylbenzoyl chloride with two equivalents of diethyl amine forms the desired compound.

Answer

The best reagents for the conversion of 1-bromo-3-methylbenzene to N,N-diethyl-3-methylbenzamide is as follows:

1)2)Mg, etherCO23)4)5) NH(CH2CH3)2, (2 equiv.)H30SOCl2DEET (the active ingredientin over the counter insectrepella

Add a comment
Know the answer?
Add Answer to:
in each reaction box place the best reagent and conditions from the list below. DEET
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT