A)
X ~ Weibull( = 0.0125, = 2/3)
Probability that signal lights function for at least 20,000 miles = P(X 20,000)
= exp[-(20000 / )alpha]
= exp[-(20000 / (2/3))0.0125]
= 0.320609
B)
Expected time to failure (in thousand of miles) = E(X) =
Suppose the random variable X represents the time to failure (in thousands of miles driven) of th...
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