9. Jordan Contour Theorem for Step Paths. Define a crossing of a closed step path σ :[a, b] → D to be a point σ(t1) in the image of σ, such that σ(t1) = σ(t2)(a ≤ t1 < t2 < b) Say that σ is simple if it has no crossings. Prove the Jordan Contour Theorem for step paths: Let σ be a simple closed step path in C. Then (i) C \ˆσ has precisely two connected components. One (call it I(σ)) is bounded, the other (call it O(σ)) is unbounded. (ii) Either w(σ, z) = 1 for all z ∈ I(σ), or w(σ, z) =−1 for all z ∈ I(σ). (iii) If z ∈ O(σ), then w(σ, z) = 0.
9. Jordan Contour Theorem for Step Paths. Define a crossing of a closed step path σ :[a, b] → D t...
Problem 4.9 (e) /(z) = and γ is parametrized by r(t), 0 z + t 1, and satisfies Imr(t)> 0, r(0) -4 + i, and γ(1) 6 + 2i (f) f(s) sin(z) and γ is some piecewise smooth path from 1 to π. 4.2 and the fact that the length of γ does not change under 4.9. Prove Proposi reparametrization. (Hint: Assume γ, σ, and τ are smooth. Start with the definition off, f, apply the chain rule to σ...
can anybody explain how to do #9 by using the theorem 2.7? i know the vectors in those matrices are linearly independent, span, and are bases, but i do not know how to show them with the theorem 2.7 a matrix ever, the the col- ons of B. e rela- In Exercises 6-9, use Theorem 2.7 to determine which of the following sets of vectors are linearly independent, which span, and which are bases. 6. In R2t], bi = 1+t...
please help me make this into a contradiction or a direct proof please. i put the question, my answer, and the textbook i used. thank you also please write neatly proof 2.5 Prove har a Simple sraph and 13 cdges cannot be bipartite CHint ercattne gr apn in to ertex Sets and Court tne忤of edges Claim Splitting the graph into two vertex, Sets ves you a 8 Ver ices So if we Change tne书 apn and an A bipartite graph...