from the given data of information
rubber | thick spring | thin spring | |
mvi |
0.5007*0.754 = 0.378 |
0.5007*0.769= 0.385 |
0.5007*0.751= 0.376 |
mvf | -0.337 | -0.299 | -0.311 |
1.346-1.328= 0.018 |
0.054 | 0.11 | |
area | 0.330 | 0.711 | 0.776 |
-0.715 | -0.684 | -0.687 N | |
favg | 26.577 N | 12.686 | 6.808N |
dp = favg* |
26.577*0.018= 0.478 |
12.686*0.054= 0.685 |
6.808*0.11= 0.749 N |
rubber ={ |-0.714| |-530|}/|-0.715| *100
=25.90%
thick = |{0.684-0.711}/0.684|*100
= 3.95%
thin = |{0.687-0.776}/0.687|*100
= 12.35%
According to the theory the mass’s change in momentum and the impulse experienced by the mass sho...
Analysis of Collisions - Impulse & Momentum Lab Name Group# Course/Section Instructor Table, Mass of Dynamics Cart 0.50193 kg Thick Spring Thin Spring Rubber Bumper 0.684 m/s Vi 0.643 m/s 0.647 m/s mvi 0.3433 kg m/s -0.400 m/s 0.3227 kg m/s -0.533 m/s Vf 0.3247 kg/s -0.626 m/s -0.3142 kg m/s 0.6389 kg m/s mvf -0.2007 kg m/s -0.544 kg m/s -0.2675 kg m/s 0.5902 kg m/s p 0.524 Ns 0.612 Ns 0.678 Ns 2.294 s 1.962 s 1.842 s...
Can someone please exaplain 7/8 thank you! Instructor Dale F0O.10 Table, Mass of Dynamics Cart Rubber Bumper Thick Spring Thin Spring O.687 O.341 -0.591 -0.296 .631 Vi (mS 0.703 0.352 Vr (ms)-6.340 -O.17 0.691 O.346 -0492 -0. 246 O592 6.634N.S (434s 1510S mv mVf 0.522 0.535 N.S Ap larea S९|१ 62१5 tr At 424 (0.885 Favg Complete the chart, and show wark. (20 points) ।।8 टी fost impulse mui.5001 (0.703)0.352 5 001 -0.340) - State one possible reason why the...