Question

Analysis of Collisions - Impulse & Momentum Lab Name Group# Course/Section Instructor Table, Mass of Dynamics Cart 0.50193 kg Thick Spring Thin Spring Rubber Bumper 0.684 m/s Vi 0.643 m/s 0.647 m/s mvi 0.3433 kg m/s -0.400 m/s 0.3227 kg m/s -0.533 m/s Vf 0.3247 kg/s -0.626 m/s -0.3142 kg m/s 0.6389 kg m/s mvf -0.2007 kg m/s -0.544 kg m/s -0.2675 kg m/s 0.5902 kg m/s p 0.524 Ns 0.612 Ns 0.678 Ns 2.294 s 1.962 s 1.842 s 2.310 s 1.952 s t 2.010 s 0.048 s 12.257 N. 0.016 s 32.800 N 0.11s Favg 6.050 N Complete the chart, and show work. (20 points)

Answer 1

Page RANKA Ans -0.544 kg m/s for Rubber Bumper O AP= mvp-mvi = Iarea = 0.524 N.S % difference ppl - Tareal. Xloo Iarea x 100 0.02 0.524 = 3.82% For thick spring AP= mvp-mvi= -0.5902 g mlet

Taree = 0: 61815 % difference 1 kpl - Saree xloo Tarea = x 100 0.0218 O of 12 = 3.56 % - For thin AP= mup -mvi= 0.63 89 spring m/s Iaree = 0°678 N.S.

lo difference = || Afl-Iareal Apl- lareal - X100 Iarea = 0.0391 x 100 0678 5.77 ./.. = Yes, dato seem to support the theory because percentage differience is below I LOL.

Note I am supposed to answer 1st question(in case of multiple questions) or first 4 (in case of multiple subparts) according to Chegg guidelines. Kindly post the other question separately if you want an answer to all the questions.