Question

Principle of Impulse and Momentum 307 > Part A - Angular velocity of the pulley Learning Goal: To be able to solve problems involving force, moment, velocity and time by applying the principle of impulse and momenturn to rigid bodies The principle of impulse and momentum states that the sum of all impulses created by the external forces and moments that act on a rigid body during a time interval is equal to the change in the linear and angular momenta of the body during that time interval. In other words, impulse is the change in momenturn. The greater the impulse exerted on a body, the greater the body's change in momentum. For example, baseball batters swing hard to maximize the impact force and follow through to maximize the impact time. The pulley shown (Figure 1) has a moment af inertia 1 -0.100 kr. 2, a radius r -0.100 m, and a mass of 20.0 kg. A cylinder is attached to a cord that is wrapped around the pulley. Neglecting bearing friction and the cord's mass, express the pulley's final angular velocity in terms of the magnitude of the cord's tension, Timeasured in N), 2.00 S after the system is released from rast. Ut the principle of angular impulse and momentum Express your answer numerically in radians per second to three significant figures. View Available Hint(s) This principle holds true for both linear and angular impulse and momentum V AX vec O ? For a rigid-body's planar motion, the equations for the linear impulse and mamentum in the x y plane are given by Ws Tradians's m(voz),+AF.dt=m(voz) Submit Figure 1 of 1 > Part B Complete previous parts) Part C Complete previous parts) Provide Feedback Next >

Answer 1

Solution : Given data? In = 0-100 kg .m² Y?0.100 m m=z0kg t=2sec 7. BD OF B Torque ting is on pulley - TY Ta 17 جم from rotational Kinematic W = Wit at o + Ty xt lot 0.106 x 2 radis O too Tw₂= 2(T rad/s) Tanswer al