Question

A Review Learning Goal: To apply the principle of work and energy to a rigid body. Submit Previous Answers Correct Part B The principle of work and energy is used to solve kinetic problems that involve velocities, forces, moments, and displacements. For a rigid body, the principle is Ti + QU1–2 = T2 where Ti is the body's initial kinetic energy, EU1-2 is the work done by external forces and moments that act on the body, and T2 is the body's final kinetic energy. For a rigid body, the kinetic energy is broken into two components: the translational kinetic energy, (1/2)mug, and the rotational kinetic energy, (1/2)IGwa, where m is the mass, vg is the velocity As shown, a unicyclist traveling at vo = 12.0 m/s approaches a hill inclined at 0 = 25.0 degrees (Figure 2). The combined mass of the unicyclist and unicycle is 91.0 kg ; the unicycle's wheel has a mass of mw = 5.00 kg , and it has a radius of r = 0.40 m . If the wheel does not slip, and the unicyclist is able to apply a constant couple moment of magnitude M = 34.0 N·m to the wheel, what is the maximum elevation, h, that the unicyclist can climb?Assume that the wheel's geometry can be approximated by a thin ring and that the unicyclist is able to keep the unicycle in a vertical position while climbing the hill. Consider the system of interest to be the unicycle's wheel and the weight of the unicycle and the unicyclist applied to a point located at the center of the wheel. Express your answer numerically in meters to three significant figures. Figure < 2 of 2 ► View Available Hint(s) ΟΙ ΑΣΦ | 11 vec ? hh = m M y W0 h La Submit ф VO Provide Feedback Next > P Pearson

Answer 1

sind X 1 / 2 v = 12 m/s mi g 1 kg 8=25° mo-5 kg r=0.40 work done by cyclist Way W.=mxo (&s=0 :) Š x W = r =mx h X' Way aomh rsinde Kinetic energy of whee KET Ž I w? Ž Lm 6,2?) ( 2013 = Ź (548.40²) ( 12 ) 360 > Kinetic energy of cyclist KEos Žmo? 5\U z(21) (16) ? - 2559=

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