Question 7
a)
Number of ways to win: 1
Number of possible outcomes: 52P5 = 2598960
P(winner) = 1/ 2598960
b)
There are 5C4 ways to get any 4 out of 5 of these numbers and there are 47C1 ways to get any 5th number that is not part of the Big Win combination.
Therefore the probability of being a Small-Fry winner = (5C4 * 47C1) / 52C5
5C4 = 5! / (4! *1!) = 5
47C1 = 47! / (1! * 46!) = 47
52C5 = 2598960
Therefore P(Small Fry) = (5 * 47) / 2598960
= 235 / 2598960
=235 / 2598960
=47 /519792
c)
Hence,
P(big or small) = 1/ 2598960 + 47 /519792
= 0.0000908
Question 8
Total number of cases = 10^4 = 10,000
T0he first digit can be ANYTHING.
The second digit has a 9/10 chance of being different from the
first.
The third digit has an 8/10 chance of being different from the
first AND from the second.
The fourth digit has a 7/10 chance of being different from the
first, second, AND third digit.
= 9/10 * 8/10 * 7/10
= 504/1000.
= 63/125,
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