Use the following Useful Information for this Problem Set: Ka (HF) 7.1 x104 Ka (HCN) 49 10-10 Ka(...
Use the following Useful Information for this Problem Set: Ka (HF) 7.1 x104 Ka (HCN) 49 10-10 Ka(H3PO47.510-3 Kai(H3Cit) 7.4 x 10-4 Kb (NH3) 18 x 10-5 Ka2(H3PO4) 6.2x 10-8 Ka2(HyCit) = 1.7×10-5 Ka3(HPO 48 x 10-13 Ka3(Ht 4.0x 10 5. You dissolve 1.00 g of pure glutamic acid in 100.0 mL of water and titrate with 0.500 M NaOH The titration curve is shown below. Using the information from this titration curve, determine the following: Kal and Kaz for...
Acid Substance or Species HE HNO2 CH3COOH HOCI HOBI ka = 7.2 x 10-4 NH3 K = 4.5 x 10-4 (CH3)3N = 1.8 x 10-5 [Co(OH)]2+ Ka = 3.5 x 10-8 [Fe(OH2)2]2+ Ka = 2.5 x 10-9 [Fe(OH2)613+ Ka = 3.5 x 10-4 [Be(OH)412+ Ka = 4.0 x 10–10 [Cu(OH)212+ Ka1 = very large HBO2 Ka2 = 1.2 x 10-2 (COOH)2 HOCN HCN H2SO4 Kb = 1.8 x 10-5 Kb = 7.4 x 10-5 Ka = 5.0 x 10-10 Ka...
Ka values: HCI HNO3 H2SO4 strong strong strong 1.3 x 10-2 7.5 x 103 7.1 x 10-4 4.5 x 10-4 1.7 x 10-4 CH3COOH CsH5NH+ H2CO3 H2PO4 HSO4- H3PO4 HF HNO2 HCOOH 1.8 x 100 5.9 x 10-6 4.2 x 10-7 6.2 x 10-8 5.6 x 10-10 4.9 x 10-10 4.8 x 10-11 4.8 x 10-13 NH1+ HCN HCO3- HPO4 6) (20 points) What is the pH of 0.065 M H2CO3 (carbonic acid)? 7) (20 points) What is the pH...
The following shows a list of weak acids and bases with their Ka and Kb values. Substances Ka Substances Kb Cyanic acid (HCN) 4.9 x 10-10 Ammonia (NH3) 1.8 x 10-5 Nitrous acid (HNO2) 4.5 x 10-4 Aniline (C6H5NH2) 4.3 x 10-10 Hydrofluoric acid (HF) 6.8 x 10-4 Pyridine (C5H5N) 1.7 x 10-9 Acetic acid (CH3COOH) 1.8 x 10-5 Methylamine (CH3NH2) 4.4 x 10-4 If you want to make a pH 8.0 buffer solution, which of the following acids or...
Explain the process of how to get the answer. The answer is highlighted. Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH HOCI HOBr HOCN HCN H2SO4 KA = 7.2 x 10-4 Ka = 4.5 x 10-4 Ka = 1.8 x 10-5 Ka = 3.5 x 10-8 = 2.5 x 10-9 K4 = 3.5 x 10-4 Ka = 4.0 x 10-10 Kai = very large Kq2 = 1.2...