answer Question 3 (16)
(a) ANOVA output: 3 points
(b) Null and alternative hypotheses in terms of the population means: 3 points Pooled estimate of the common variance: 2 points
Value of the test statistic: 2 points
Null distribution: 2 points
The P-value: 2 points
Conclusion in plain language: 2 points
the following is the data use stat crunch or excel
Category code score C 1 45 C 1 53 C 1 72 C 1 55 C 1 67 C 1 53 C 1 66 C 1 54 C 1 53 C 1 67 C 1 60 C 1 64 C 1 69 C 1 52 C 1 74 C 1 58 C 1 53 C 1 66 C 1 66 C 1 71 H 2 79 H 2 95 H 2 81 H 2 74 H 2 68 H 2 84 H 2 78 H 2 77 H 2 85 H 2 72 H 2 86 H 2 71 H 2 67 H 2 77 H 2 83 H 2 73 H 2 76 H 2 86 H 2 83 H 2 75 Q 3 58 Q 3 66 Q 3 67 Q 3 68 Q 3 64 Q 3 57 Q 3 58 Q 3 57 Q 3 75 Q 3 60 Q 3 63 Q 3 55 Q 3 64 Q 3 51 Q 3 60 Q 3 55 Q 3 61 Q 3 63 Q 3 76 Q 3 64 T 4 51 T 4 57 T 4 73 T 4 67 T 4 63 T 4 77 T 4 67 T 4 81 T 4 70 T 4 82 T 4 61 T 4 58 T 4 80 T 4 68 T 4 76 T 4 60 T 4 69 T 4 68 T 4 86 T 4 64 HT 5 78 HT 5 85 HT 5 86 HT 5 92 HT 5 84 HT 5 78 HT 5 79 HT 5 78 HT 5 95 HT 5 81 HT 5 83 HT 5 76 HT 5 83 HT 5 72 HT 5 81 HT 5 70 HT 5 81 HT 5 90 HT 5 95 HT 5 84 QT 6 55 QT 6 80 QT 6 67 QT 6 89 QT 6 90 QT 6 72 QT 6 75 QT 6 61 QT 6 68 QT 6 56 QT 6 63 QT 6 66 QT 6 64 QT 6 65 QT 6 62 QT 6 70 QT 6 83 QT 6 72 QT 6 65 QT 6 73
(a)
Answer Question 3 (16) (a) ANOVA output: 3 points (b) Null and alternative hypotheses in term...
QUESTION- Before applying any inferential tools to the data, always conduct a preliminary analysis to get an idea about the association between your variables. In addition, the results of a statistical analysis are valid only if the appropriate assumptions for the model to be used are valid. The assumptions for the ANOVA are that the data are independent and come from normal populations with equal variances (or standard deviations). In particular: (a) Obtain the summary statistics (sample size, mean, standard...
Problem #1: Consider the below matrix A, which you can copy and paste directly into Matlab. The matrix contains 3 columns. The first column consists of Test #1 marks, the second column is Test # 2 marks, and the third column is final exam marks for a large linear algebra course. Each row represents a particular student.A = [36 45 75 81 59 73 77 73 73 65 72 78 65 55 83 73 57 78 84 31 60 83...
DATA: ( You will have to paste it to a text editor and format it to be entered into statcrunch - sorry for inconvenience but I could not find another way to post the data) Strategy Code Score C 1 45 C 1 53 C 1 72 C 1 55 C 1 67 C 1 53 C 1 66 C 1 54 C 1 53 C 1 67 C 1 60 C 1 64 C 1 69 C 1 52...
DATA: ( You will have to paste it to a text editor and format it to be entered into statcrunch - sorry for inconvenience but I could not find another way to post the data) Strategy Code Score C 1 45 C 1 53 C 1 72 C 1 55 C 1 67 C 1 53 C 1 66 C 1 54 C 1 53 C 1 67 C 1 60 C 1 64 C 1 69 C 1 52...
DATA DATA: ( You will have to paste it to a text editor and format it to be entered into statcrunch - sorry for inconvenience but I could not find another way to post the data) Strategy Code Score C 1 45 C 1 53 C 1 72 C 1 55 C 1 67 C 1 53 C 1 66 C 1 54 C 1 53 C 1 67 C 1 60 C 1 64 C 1 69 C 1...
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89 67 84 74 58 51 63 68 84 65 57 76 58 75 72 67 64 74 95 53 77 86 90 80 70 67 76 62 91 70 63 78 49 61 77 57 83 67 107 67 80 73 94 80 73 74 67 72 68 79 73 121 63 77 70 61 75 66 79 54 76 86 84 72 65 75 63 91 72 64 99 81 58 70 58 58 90 66 64 80...
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