Homework Answers
power outage probability given as P(outage)=0.02
for Rayleigh fading the
formula for power outage probability P(outage)=1-exp(-P0/Pr)
where P0=-85dBm
i.e 0.02=1-exp(-P0/Pr)
0.98=exp(-P0/Pr)
apply natural logerthim both sides
ln(0.98)=(-P0/Pr)
-0.0202=(-P0/Pr)
therefore Pr=P0/0.0202 (dBm) since -85dBm=-115dB
Pr=115/0.0202 =5692 dBm
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