Question

Raj deposits 50 into a fund at the end of each month for 5 years. The fund pays interest at an an...

Raj deposits 50 into a fund at the end of each month for 5 years. The fund pays interest at an annual effective rate of i. The total amount of interest earned during the last month of year 5 is 13. Calculate the accumulated amount in Raj's account at the end of year 5

A) 3325

B) 3350

C) 3375

D) 3400

E) 3425

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Answer #1

This can be solved by trial and error

let us construct a schedule of investment value using 5% interest rate as below :

D3 A -83*5%/12 Beginning 1 Month Value Deposit Interest Ending Value 50.00 100.21 150.63 201.25 252.09 303.14 354.41 405.88 4

First deposit is made at the end of 1st month, so interest is zero in 1st month

In the second month onward until 60th month,

interest = beginning value * interest rate / 12   (as the interest is calculated monthly)

ending value = beginning value + interest + deposit

With 5% interest rate, the ending value and interest paid in last month of year 5 are as below :

D61 fel-B61*5%/12 Beginning 1 Month Value 57 58 59 Deposit Interest Ending Value 3,146.28 56 3,083.4450.00 12.85 57 3,146.285

In the question, the interest paid in last month of year 5 is 13. So we try again with a lower interest rate of 4.5% :

D4 fel -84*4.5%/12 Beginning 1 2 Month Value Deposit Interest Ending Value .00 50.00 0.00 1 250.00 50.00 3 100.1950.00 0.19 0

D61 fel -861*4.5%/12 Beginning 1 Month Value 57 58 59 60 61 Deposit Interest Ending Value 3,109.25 56 3,047.82 50.00 11.43 57

Interest paid in last month of year 5 is 12.36. We try again with 4.71% interest :

D3 fy -83*4.71%/12 Beginning 1 Month Value 1 2 3 100.20 50.00 4 150.59 5 201.1850.00 Deposit Interest Ending Value 50.00 100.

D61 fl -861*4.71%/12 Beginning 1 Month Value 56 57 58 59 55 3,000.9350.00 56 3,062.71 50.00 12.02 57 583,187.0050.00 12.51 59

With 4.71% interest rate ,we can see that the interest paid in last month of year 5 exactly equals 13.00

The ending value of this investment is 3,375.26

The answer is C

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