Question

You may need to use the appropriate technology to answer this question A manufacturer produces lots of a canned food product. Let p denote the proportion of the lots that do not meet the product quality specifications. An n 21, c-0 acceptance sampling plan will be used (a) Compute points on the operating characteristic curve when p0.01, 0.03, 0.10, and 0.20. (Round your answers to four decimal places.) p 0.01 p 0.03 p = 0.10 p-0.20 (b) Plot the operating characteristic curve 1.00 ao 0.80 0.60 0.40 0.20 0.00 1.00 0.80 0.60 0.40 0.20 0.00 10 15 20 10 15 20 Percent Defective in the Lot Percent Defective in the Lot 1.00 1.00 o 0.80 “ 0.80 0.60 0.60 0.40 0.20 0.00 0.40 0.20 0.00 10 15 20 10 15 20 Percent Defective in the Lot Percent Defective in the Lot (c) What is the probability that the acceptance sampling plan will reject a lot containing 0.03 defective? (Round your answer to four decimal places.)

Answer 1

a)Given n 21,c 0,p 0.01 21Co (0.01) (1-0.01)' 0.809728 Given n 21,c 0,p 0.03 21C (0.03) (1-0.03)10 0.527481 Given n 21,c 0,p 0.10 -21C0 (0.10) (1-0.10) 0.109419 Given n 21,c 0,p 0.20 22c, (0.20) (1-0.20) 0.009223

b) Correct answer: Option (B)

1.00 0.80 0.60 0.40 0.20 0.00 10 15 20 Percent Defective in the Lot

c) 1-PKs0)-1-P(X = 0) = 1-21G (0.03)' (1-0.03)2-0 1 1-0.527481 0.472519