Homework Answers
a)for p =0.01 ; P(Accepting the lot )= (1-0.01)^35 =0.7034
| p | P(accepting the lot) |
| 0.01 | 0.7034 |
| 0.03 | 0.3444 |
| 0.1 | 0.0250 |
| 0.2 | 0.0004 |
c)
| P(reject) = | 1-0.0250 =0.9750 | |
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Can someone help with the analysis of this NMR spectrum for the
synthesis of benzyl methyl ether. (Benzyl chloride, diethyl ether
and then added sodium methoxide to produce benzyl methyl
ether)?
What I have so far is:
4 different protons:
3 x 1H on the benzene ring, doublet
2 x 1H on benzene ring, either side of O, doublet
2H on Carbon beside O, quartet
3H on end of alkene with O, triplet
I don't understand where they match up...
Need to find the identity of the unknown compound using this
information.
Boiling point: 187
%C: 79.37
%H: 8.88
Bromine test: no reaction
Permanganate: no reaction
Jones Oxidation: no reaction
Sodium Hydroxide: no reaction
13C NMR Common Name: IUPAC Name: CAS No.: Zoom Out Solvent: BP: MP: 1.00 0.90 0.80 0.70 0.60 0.50 0.40 0.30 0.20 0.10 0.00 140 120 100 80 60 40 20 0 OK SAVE 1H NMR Common Name: IUPAC Name: CAS No.: Zoom Out Solvent: BP:...
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