Question

1.-5. Match each pair of compounds on the left and their corresponding melting points (m.p.) or boiling points (b.p.) in °C to the major reason why they increase. Answers may be repeated. All answers should begin with more….

1. (CH₃CH₂)₂O (b.p. 35), butan-1-ol (b.p. 118)                                                                                                                                     
2. 2,2,4-trimethylpentane(the 100 % octane standard in gasoline, m.p. -107), heptane (m.p. -91)                              
3. heptane (the 0 % octane standard in gasoline, b.p. 98), 2,24-trimethylpentane (b.p. 99)                                      
4. octane (m.p. -57), cubane (m.p. 130)                                                                                                                                   
5. CH₃SH (the smell of natural gas, b.p. 6), methanol (b.p. 65)                                                                                                       

1. weight          b. polar bonds    c. rotational symmetry                   d. van der Waal interactions        e. hydrogen bonds

Answer 1

en bonding of methanal o, Jaaelr to highr p than CHSH ร/SCH3SH ghoud s no ?het molecula.khuelnogen. bend hj 2,2 molecular mass/uueftk, 2 ,4.hi =之more thour heptane molecu CHig tule huptane is CyHis hence molar move wefaht

butane -1-ol shesyecrogen bond bonding (dueto absenu of H atom diye attauh to oxyain atom) fnkemetecular en bendu houding CH -t hephane 2,2,4 teimetuulpentance . nore van de waal inler act n dacu to heptane