Question

An athletics trainer wants to measure the effectiveness of his training skills with a population ...

An athletics trainer wants to measure the effectiveness of his training skills with a population of 63 athletes. He selects athletes by waiting at the training facility and pulling aside every third athlete to give him or her a questionnaire.

1. A specific question on the questionnaire asks about verbal coaching effectiveness on a 0-10 scale (0 = extremely confusing to 10 = extremely clear) with the following scores:

           

                        0, 9, 8, 8, 5, 4, 3, 2, 6, 5, 8, 1, 4, 10, 5, 8, 6, 7, 5, 4, 9

Calculate the mean, median, and mode of these scores. Which is the best measurement to report verbal coaching effectiveness? Why?

2. Calculate the variance and standard deviation of the sample. What conclusions about verbal coaching effectiveness can you make with this added information?

3. The trainer decided to change his method after the initial sample and then re-sampled his athletes (same sample method) to see if there was an improvement in his verbal coaching effectiveness score. The new average verbal coaching effectiveness score is 7.2 with a standard deviation of 2.2. What is the probability that a sample mean selected from this population would show no change (0) or a negative change (less than 0) after the new lectures were implemented?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution1:

Given scores

0, 9, 8, 8, 5, 4, 3, 2, 6, 5, 8, 1, 4, 10, 5, 8, 6, 7, 5, 4, 9

mean=sum of scores/total scores

=117/21

mean =5.571429

median is middlemost value after sorting data in ascending order(small to big)

Ascendng order is

0 1 2 3 4 4 4 5 5 5 5 6 6 7 8 8 8 8 9 9 10

median=5

mode is most repeating item

mode =5 as 5 repeats 4 times in data

median is the best measure as it is not affected by outliers.

Solution2:

x xbar x-xbar (x-xbar)^2
0 5.571429 -5.571429 31.04082
9 5.571429 3.428571 11.7551
8 5.571429 2.428571 5.897957
8 5.571429 2.428571 5.897957
5 5.571429 -0.571429 0.326531
4 5.571429 -1.571429 2.469389
3 5.571429 -2.571429 6.612247
2 5.571429 -3.571429 12.75511
6 5.571429 0.428571 0.183673
5 5.571429 -0.571429 0.326531
8 5.571429 2.428571 5.897957
1 5.571429 -4.571429 20.89796
4 5.571429 -1.571429 2.469389
10 5.571429 4.428571 19.61224
5 5.571429 -0.571429 0.326531
8 5.571429 2.428571 5.897957
6 5.571429 0.428571 0.183673
7 5.571429 1.428571 2.040815
5 5.571429 -0.571429 0.326531
4 5.571429 -1.571429 2.469389
9 5.571429 3.428571 11.7551
total 149.1429
xbar=mean=
variance=149.1429/21-1
variance=149.1429/20
variance=7.457143

standard deviation=sqrt(variance)

=sqrt( 7.457143)

standard deviation =2.730777

mean=5.57

stddev=2.73

mean-sd=5.57-2.73=2.84

mean+sd=5.57+2.73=8.3

data is having less spread.

overall verbal coaching is effective

Add a comment
Know the answer?
Add Answer to:
An athletics trainer wants to measure the effectiveness of his training skills with a population ...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The stem-and-leaf plot below shows the marathon training times (in minutes) for a random sample of...

    The stem-and-leaf plot below shows the marathon training times (in minutes) for a random sample of 30 female runners. Training Times (in minutes) of Female Runners 8 99 Key: 17 8 = 178 18 0 0 0 0 1 2 3 4 6 6 7 9 19 0 0 0 3 4 5 5 6 6 20 0 0 1 2 3 Provided the data from the stem-and-leaf plot above answer the following questions. 1 a) Use the sample to...

  • The stem-and-leaf plot below shows the marathon training times (in minutes) for a random sample of...

    The stem-and-leaf plot below shows the marathon training times (in minutes) for a random sample of 30 female runners. Training Times (in minutes) of Female Runners 17 8 9 9 Key: 17 8 = 178 18 0 0 0 0 1 2 3 4 6 6 7 9 19 0 0 0 1 3 4 5 5 6 6 20 0 0 0 1 2 3 Provided the data from the stem-and-leaf plot above answer the following questions. a) Use...

  • Part (V) to (Vii) A large number of people worldwide take the GMAT exam each year...

    Part (V) to (Vii) A large number of people worldwide take the GMAT exam each year as they apply for MBA programs. Administrators of the test suggest that from past experience the distribution of GMAT exam scores is closely approximated by a normal distribution with mean 1F525 and standard deviation ơ-100 (i)Assuming the population distribution of GMAT exam scores is normal, what is the probability that a person randomly drawn from those taking the test would have a test score...

  • A large number of people worldwide take the GMAT exam each year as they apply for...

    A large number of people worldwide take the GMAT exam each year as they apply for MBA programs. Administrators of the test suggest that from past experience the distribution of GMAT exam scores is closely approximated by a normal distribution with mean 1F525 and standard deviation ơ-100 (i)Assuming the population distribution of GMAT exam scores is normal, what is the probability that a person randomly drawn from those taking the test would have a test score between 510 and 550?...

  • 25 Anormal population - 0 - 8. A random sample and scores from 54 Wurthe-wore for...

    25 Anormal population - 0 - 8. A random sample and scores from 54 Wurthe-wore for this sample is population has a mean of 24. A random sample of 4 scares is obtained from a mal population with probability of obtaining met greater than 22 for this sample! - 20 and a t West - 20 the following samples is deur likely to be obtained For normal perelation with a Band for a sample of n = 4 X- 5...

  • Please m asking for assistance on statistics Q10. A population consists of the following N-5 scores:...

    Please m asking for assistance on statistics Q10. A population consists of the following N-5 scores: 0, 6, 4, 3, and 12 a. Compute u ando for the population b. Find the 2-score for each score in the population c. Transform the original population into a new population of N = 5 scores with a mean of u = 100 and a standard deviation of a = 20 Q11. For a sample with a mean of M = 51, a...

  • 1. A C level confidence interval is described as what? (3 points) Oan interval computed from...

    1. A C level confidence interval is described as what? (3 points) Oan interval computed from a data sample by a method that has the probability C of producing an interval containing the true value of the parameter any interval within the margin of error O an interval with a margin of error C that is also correct C% of the time Oany interval that follows the 68-95-99.7 rules Oan interval computed from a data sample that guarantees that the...

  • Research question: In the population of all American adults, how strong is the relationship between age...

    Research question: In the population of all American adults, how strong is the relationship between age and reaction time? Data were collected from a representative sample of 500 American adults concerning their ages (in years) and reaction times (in milliseconds). What procedure should be used to estimate the strength of this relationship in the population? CI for single mean CI for single proportion CI for difference in means CI for difference in proportions CI for correlation 2Research question: To what...

  • please answer all question 16-20 Question 16 2 pts The population mean for a standardized test...

    please answer all question 16-20 Question 16 2 pts The population mean for a standardized test is 250. A research study with N = 30 adults from Virginia had a mean score of 260, with a 95% confidence interval of the mean reported as [248, 272]. What decision should be made based on this confidence interval? o Run the hypothesis test again o Accept the research hypothesis o Reject the null hypothesis o Fail to reject the null hypothesis Question...

  • Please answer part a) through part f) of the question below. Thank you. Question 2 Administrators...

    Please answer part a) through part f) of the question below. Thank you. Question 2 Administrators at ACME High School wanted to know which of four instructional methods for mathematics is best. The four methods were lecture only (L), lectures with remedial textbook assistance (LR), lectures with computer assistance (LC), and computer instruction only (C). At the end of five weeks, the students were given a common exam. The scores on the exams are below. Student L L/R L/C C...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT