Question

ProblemT. A charge qi 8.4HC travels at a speed of Vi-800 m/s through a magnetic field that of 82T and makes an angle of θ-Sp with the field. The mass of the charge is 2.8x10 kg (a) (5 pts.) Find the magnitude of the force on the charge. Indicate the direction of F in the diagram. (b) Ơpts.) The acceleration of the charge. 4 C

Answer 1

a) magnetic force is given by the formula,

F= q*(v x B) {cross product of v and B}

F = qvB*sin($\phi$) {$\phi$ is the angle between v and B,here $\phi$= 180-$\theta$ = 180-50 = 130^o}

F= 8.4*10^-6*800*8.2*sin(130)

F = 0.0422 N

direction of magnetic force is into the page

b) acceleration, a = F/m = 0.0422/(2.8*10^-27)

a = 1.507*10²⁵ m/s²