Question

Problem 7. A charge qi=8.2 uC travels at a speed of V-1050 m/s through a magnetic field that of 6.2T and makes an angle of = 75° with the field. The mass of the charge is 2.8x10-kg. (a) (5 pts.) Find the magnitude of the force on the charge. Indicate the direction of F in the diagram. (b) pts.) The acceleration of the charge. *82fuc & V8

Answer 1

Part A

The force on the charge is given by

$F=qvB\sin\theta=(8.2\times 10^{-6})\times (1050)\times 6.2\times \sin75=0.0516\mathrm{N}$

The direction of this force is into the page, perpendicular to both the velocity and the magnetic field.

Part B

The acceleration of the charge is

$a=\frac{F}{m}=\frac{0.0516}{2.8\times 10^{-27}}=1.84\times 10^{25}\mathrm{m/s^2}$