Question

2. Show that the scattering cross section for a "hard sphere" is given by 22mE sin2 a 2mE h starting from the Schrodinger equation expressed in spherical coordinates, i.e R=ER 2m drrdr where ψ(r) (m, V(r)=lo. 47 sin' δ0 and the fact that σ=--k2_- r

Answer 1

To solve this problem the details calculations are given below
kr r44 21T 6

ち~ 2hp ち っと": 2nm