Question

please identify the structure of the compound with explanation MS IR H-NMR 13C NMR. The molecular formula is not available just try to get us as close as possible you can

Even though the molecular formula is not given get us close as possible as you can

Electron ionization (El-MS) 167 75 50 25 139 84 63 113 7074 87 28 39 50 e 98 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 180 : m/iz Varian Resolutions Pro 120 110 100 90 80 70 60 50 12043 13929 40 30 20 10 380-3600一3400- 3200-3000-2800-2600一2400-2200-2000ー180_1600-400-1200 000- 80 600 Wavenumber post! 2 Itseg 4 6 b9p1 3b1 000Z 2 0 PC-4 .000 r2_-0.000ppm, ADDRESS F1-12.000ppm, MI-0.50㎝, MAXI-10000 , 00cm, FREQUENCY IHz] 5624.100 INTENSITY PPM 11.2433 4.27 9.22 9.42 8.59 11.31 5.75 9.20 4.83 5.93 9.90 5.11 15.00 15301.2 28107.5 4058.324 8.1131 28171.3 4050.520 8.0975 4 30658.1 3746.4677.4896 30724.43738.359 7.4734 3697.938 7.3926 7 31115.03690.608 7.3780 31055.0 8 31179.4 3682.737 7.3622 9 31986.03584.111 7.1651 10 32046.83576.682 7.1502 3569.224 7.1353 12 47589.71676.307 3.3511 11 32107.8 13 51071.5 1250.609 2.5001 5.84 94961 0b981 229Lt 3 6 8 し000 8 8- t-restored spin-echo 13c spectram vith 18 decoup)ing e t-restored spin-echo 13c spectrun vith 18 decoupling CD SOCD 13C(18) dept135 dept90 I50 l60

Answer 1

on summing up all the spectra

wr have

one benzene ring

one secondary amine

one nitro group

two aliphatic SP3 carbon

two SP3 hydrogen

one intra molecular hydrogen bond

please find attached file for detailed information

o F 2. 2 N H IH NMR Bondina with NO Hydrogen Bondin 33so-3310 CHH Shtng Seconday anine 1499 due o N on Addin a Benene Ring → a Secondary → a N.he group tur aliphahk Hydrogen