Draw the remaining product of the following reaction.
The concept used to solve this question is formation of amide using acyl chloride.
Acid chlorides reacts with primary amine and forms a secondary amide.
Acyl chloride reacts with nucleophile and forms a substitution product with HCl as a by-product.
The given amine is as follows:
It is a primary amine.
The nitrogen is bonded with two hydrogen atoms and one ethyl group.
So, it is a primary amine.
The reaction is as follows:
The product is as follows:
Treatment of benzoyl chloride with two equivalents of ethyl amine and forms N-ethylbenzamide and ethyl ammonium salt.
Here one equivalent of ethyl amine acts as a nucleophile to replace the -Cl group and forms the substitution product. The second equivalent of ethyl amine reacts as a base with the HCl by product and forms an ethyl ammonium salt.
The product is as follows:
The product is as follows:
draw the remaining product of the following reaction. be sure to specify any nh bonds
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction
Draw the remaining product of the following reaction Cl + 2 HC- CH2- NH2 > H3C-CH2-NH, Cl- +
Can anyone help me? The remaining product will be an ester.
Draw the remaining product of the following reaction.
Draw the remaining product of the following reaction CI +2 HC- CH2- NH2 > H,C-CH2-NH CI +
Suggest a mechanism and predict the major product for the
following reaction: (Draw the remaining curved arrows and the
product formed in the first step of the mechanism. Include lone
pairs and charges in your answer.)
1) LAH 2) H20