Question

Consider the following method

1. double calculateMin(int A, int B){

2. int minVal = A;

3. if (B<A){

4. minVal = B;

5. }

6. return minVal; 7.

7. }

Describe two mutation operators and use them to create two mutants.

Answer 1

First mutation operators can be operands A and B
First mutant if where we interchange operand A and B as below
double calculateMin(int A, int B){
int minVal = A;
if (A<B){
minVal = B;
}
return minVal;
}

The above code will now always return the largest of the two numbers A and B as such the test case will fail

=====================================================================================

Second mutation operators can be B<A, here we change less than operator to greater than operator
double calculateMin(int A, int B){
int minVal = A;
if (B>A){
minVal = B;
}
return minVal;
}

The above code will now always return the largest of the two numbers A and B as such the test case will fail