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1. Consider a spin-0 particle of mass m and charge q moving in a symmetric three-dimensional harmonic oscillator potential wi
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Answer #1

2. Linear crystal optics for monochromatic plane waves

D =

1

2

De

−i(ωt−k·r) + D∗

e

i(ωt−k·r)

. (2.3)

The actual fields are represented by the real quantities P, E, and D, but

for many calculations it is more convenient to use the complex envelope

functions D, E, and P . These complex vectors are in general functions of

(x, y, z, t). However, for monochromatic plane waves, they are independent

of space and time so we omit these arguments in this chapter, and treat

the envelope functions as simple complex vectors.

We substitute the expansions of Eqs. (2.1)-(2.3) in the wave equation,

Eq. (1.13)

∇ × ∇ × E = −µ◦

2

∂t2 D = −µ◦

2

∂t2

ǫ◦E + P

. (2.4)

The operator ∇ becomes (±ik) when it operates on the exponent (±ik ·

r). Similarly the operator (∂/∂t) becomes (±iω) when it operates on the

exponent (±iωt). Making these substitutions in Eq. (2.4) and equating the

positive (or negative) frequency components on each side of the equation

yields

k × k × E = −µ◦ω

2D. (2.5)

In deriving this equation we assumed that E and D do not change on prop-

agation, so this is a wave equation for eigenpolarized light. This expression

implies that D must be normal to k, but D is not necessarily parallel to

E. However, k, D, and E must lie in a single plane.

We use a similar procedure to rewrite the Poynting vector equation to find

the energy flow for monochromatic plane waves. We start with Eq. (1.16),

the general Poynting vector equation,

S =

1

µ◦

E × B = E × H. (2.6)

For monochromatic plane waves the third Maxwell equation, Eq. (1.3),

relates H to E for eigenpolarized light in a nonmagnetic material by

H =

k × E

µ◦ω

. (2.7)

Substituting the expansions for E and H in Eq. (2.6), equating equal fre-

quency components, and using Eq. (2.7) plus

ǫ◦µ◦c

2 = 1, (2.8)

we arrive at

S =

nǫ◦c

2

|E|

2 eˆ× kˆ × eˆ,

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