A motor has a nameplate with the following data: 50 HP 60 Hz 107.8/53.9 AFL 240 480 Volts 1530 RP...
A motor has a nameplate with the following data: 50 HP 60 Hz 107.8/53.9 AFL 240 480 Volts 1530 RPM NEMA Design D Determine the speed at which the motor will produce maximum torque.
You purchase a motor in Germany designed to run at 415 Volts, 50 Hz. It has 75 kW output power, runs at 2978 RPM and has 240 N-m of rated torque. You ship it Canada and run it at 480 Volts, 60 Hz. What will be the new torque in N-m? (Round your answer to the nearest integer).
3. The nameplate of a Y-connected synchronous motor has the following information. Hp 20,000, RPM 1800, PF 1.0 Volts 6600, Ampere 1350, Phase 3, Frequency 60 The per-unit reactance Excitation voltage 120, Amp 5.5 is X, = 0.95, and the per-unit resistance is R = 0.012 A. Determine X, and R, in ohms. B. For rated (full-load) condition (i) Determine the output torque in Nm. (ii) Determine the rotational loss. (iii) Determine the efficiency.
10.17.A split-phase motor has this information on its nameplate: 3/4 hp 1,725 rpm 13.8/6.9 A Full-load power factor: 0.70 Insulation class B Code U 115/230 V The motor is wired for low-voltage operation. (a) What is the synchronous speed of this motor? (b) What is the maximum locked-rotor cur rent it should draw if wired for 115-V opera- tion? (c) What is the full-load torque (lb ft)?
2) A 480 V, 60 Hz, 400 hp 0.8 PF-lagging eight-pole A-connected synchronous motor has a synchronous reactance of 0.6 and negligible armature resistance. Ignore the mechanical and core losses. The magnitude of the internal machine voltage is 480 V when the field current is 4 A. Assume magnetic linearity. Initially, the motor operates at the rated conditions. a) Find the speed of this motor. b) Find the armature and field currents. c) What is the developed torque? What is...
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor has the following equivalent circuit parameters. R1 = 0.2 Ω, , , Xm = 12Ω.The rotational loss is 500 W. For a slip of 5%, calculate (a) The motor speed in rpm and radians per sec (b) The current drawn by the motor from the power supply (c) The stator cu-loss (d) The air gap power (e) The rotor cu-loss (f) The shaft power (g)The developed torque and the shaft torque (h) The efficiency of the motor Use...
3) A four pole 75 HP 50 Hz induction motor with an efficiency of 93.4% has equivalent resistance and equivalent reactance per phase of 0.3000and 0.78 000OTHE blocked rotor voltage per phase is 175V. If the rotor is turning at 1425 rpm, determine synchronous speed, slip, rotor impedance, rotor current, total three phase apparent power crossing the air gap, its active and reactive components, rotor power factor, shaft speed, mechanical power developed and developed torque. (30 Points)
A given load is driven by a 480 V 8-pole 60 hp three-phase synchronous motor with the following data below. Determine the developed power and developed torque. Load: T = 0.015 x w?, TRL 0.03x ur Motor: X1.8 Q, E-300 V 4. jXd Van A given load is driven by a 480 V 8-pole 60 hp three-phase synchronous motor with the following data below. Determine the developed power and developed torque. Load: T = 0.015 x w?, TRL 0.03x ur...
The three-phase wye-connected induction motor nameplate gives the following information: 400 V, 1755 rpm, 60 Hz. Rotor speed at no-load is 1799 rpm. At rated voltage and frequency motor core losses are 400 W. At rated rotor speed, mechanical losses are 400 W. The available parameters of the motor conventional equivalent circuit (6-parameters IEEE model) are: R1 = 0.2 Ω, R’2 = 0.2 Ω, X1 = 0.5 Ω, X’2 = 0.2 Ω and Xφ = 20.0 Ω. In all calculations,...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...