TITRATIONA TITRATION B -HCL-titrated with-dNaal CHIDOL titrated with NADH-_ Volume of second reag...
any help is greatly appreciated TITRATION A TITRATİON B HCL titated with 6NC.l CLİlbal titrated with NA -- Volume of second reagent added (mL Volume of second reagent added (mL) 3.02 41.12 0.0 5.0 10.0 15.0 20.0 21.0 0.0 5.0 10.0 15.0 20.0 21.0 22.0 2.25 52 5 43 23.0 24.0 25.0 2-10 L-35 11.55 11.15 27.0 28.0 29.0 29.0 12.02 2.25 12.33 12.40 2.45 0.0 35.0 40.0 45.0 50.0 12 40.0 2.25 45.0 12.3Y 2.니 ANSWERS TO QUESTIONS 1....
USE EXCEL TO CALCULATE THE FREQUENCIES AS SHOWN BELOW. PLEASE PROVIDE EXCEL FORMULA USED. Frequency Distribution Low High Bins Frequency -67.0 -56.6 (-67, -56.6] -56.6 -46.2 (-56.6, -46.2] -46.2 -35.8 (-46.2, -35.8] -35.8 -25.4 (-35.8, -25.4] -25.4 -15.0 (-25.4, -15] -15.0 -4.6 (-15, -4.6] -4.6 5.8 (-4.6, 5.8] 5.8 16.2 (5.8, 16.2] 16.2 26.6 (16.2, 26.6] 26.6 37.0 (26.6, 37] 37.0 47.4 (37, 47.4] 47.4 57.8 (47.4, 57.8] 57.8 68.2 (57.8, 68.2] 68.2 78.6 (68.2, 78.6] 78.6 89.0 (78.6, 89]...
Refer data from conductometric titration of a solution containing Mg2+ and SO42- with BaCl2. (a) Determine the concentration of sulfate ion in the 40mL aliquot if it was titrated with 0.05M BaCl2 solution. (b) Use these molar ionic conductances to explain the SHAPE of the titration curve. Cl- = 76.4 Ba2+ = 127.3 SO4 2- = 160.0 Mg2+ = 106.0 Volume Barium chlol Cond 0.0 5.0 10.0 15.0 20.0 25.0 27.0 29.0 31.0 32.0 33.0 34.0 35.0 40.0 42.0 44.0...
Days Status 29.0 1 42.0 1 38.0 1 40.0 1 43.0 1 40.0 1 30.0 1 42.0 1 30.0 2 35.0 2 39.0 2 28.0 2 31.0 2 31.0 2 29.0 2 35.0 2 29.0 2 33.0 2 26.0 3 32.0 3 21.0 3 20.0 3 23.0 3 22.0 3 Pr d) OBTAIN A 9 CONFIDENCE INTERVAL FOR THİS CONTRAST.
A 50.0 mL solution of 0.137 M KOH is titrated with 0.274 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCI. 0.00 mL pH = 5.00 mL pH = 12.5 mL pH = 20.0 mL pH = 24.0 mL pH = 25.0 mL pH= 26.0 mL pH = 29.0 mL pH =
A 50.0 mL solution of 0.110 M KOH is titrated with 0.220 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl. 0.00 mL pH = 7.00 mL pH = | 12.5 mL pH = 20.0 mL pH = 24.0 mL pH = 25.0 mL pH = 26.0 mL pH = 29.0 mL pH =
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with 0.200 M NaOH. What is the pH of the solution when 0.00 mL, 10.0 mL, 12.5 mL, 20.0 mL, 25.0 mL, and 40.0 mL E.S RaWeMA 5.83 x 10 8) have been added? (Ka1= 2.46 x 10, Ka2 ANSWER: 0 mL = 2.315, 10.0 mL= 4.211 (or 4.213), 12.5 mL = 5.422, 20.0 mL 7.410, 25.0 mL = 9.966, 40.0 mL = 12.664 11....
A 50.0 mL solution of 0.146 M KOH is titrated with 0.292 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl. 0.00 mL pH = 6.00 mL pH = 12.5 mL pH = 1 20.0 mL pH = 24.0 mL pH = 25.0 mL pH= 26.0 mL pH = 29.0 mL pH =
SnowGeese File: Trial Diet WtChange DigEff ADFiber 1 Plants -6.0 0.0 28.5 2 Plants -5.0 2.5 27.5 3 Plants -4.5 5.0 27.5 4 Plants 0.0 0.0 32.5 5 Plants 2.0 0.0 32.0 6 Plants 3.5 1.0 30.0 7 Plants -2.0 2.5 34.0 8 Plants -2.5 10.0 36.5 9 Plants -3.5 20.0 28.5 10 Plants -2.5 12.5 29.0 11 Plants -3.0 28.0 28.0 12 Plants -8.5 30.0 28.0 13 Plants -3.5 18.0 30.0 14 Plants -3.0 15.0 31.0 15 Plants -2.5 ...
Interpret pH titration plots. Answer the following about the titration plot shown below, involving a monoprotic acid and base. 20 mL of 0.1M titrand titrated with 0.1M titrant. Data points at 1 mL increments. 14.0 120 tot - ܬ ܐܬܐܠ ܠܗܬܐܩܟܬ 0.0 10.0 20.0 30.0 40.0 50.0 Volume of titrant (mL) (a) Is the species being titrated an acid or a base? - (b) Is the species being titrated strong or weak? -- (c) What is the value of K,...