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UESTION 7 Most investment firms provide estimates of systematic risks of securities, called betas. A stocks beta measures th

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Answer #1

x <- c(19,-14.7,-26.5,37.2,23.8,-7.2,6.6,18.4,32.4)
y <- c(57.4,-13,-24.4,50.4,17.3,-9.3,0.7,-11.8,13.1)
model <- lm(y~x)
summary(model)

Call:
lm(formula = y ~ x)

Residuals:
    Min      1Q  Median      3Q     Max 
-28.946  -5.060  -1.744   1.793  39.675 

Coefficients:
            Estimate Std. Error t value Pr(>|t|)  
(Intercept)  -0.6086     7.6636  -0.079   0.9389  
x             0.9649     0.3349   2.881   0.0236 *
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 20.73 on 7 degrees of freedom
Multiple R-squared:  0.5426,    Adjusted R-squared:  0.4772 
F-statistic: 8.302 on 1 and 7 DF,  p-value: 0.02361

a)

y^= -0.6086 + 0.9649 x

b1 = 0.9649

This is defensive

b)

error term variance = standard error ^2 = 20.73^2 =

429.9 

c)

y^= -0.6086 + 0.9649 *10

= 9.0404

d)

coefficient of determination = R^2 = 0.5426

it means 54.26 % of variation is explained by this model

strength - moderate

e)

predict(model, data.frame(x =10),interval = "prediction")
       fit       lwr      upr
1 9.040546 -42.63862 60.71971

95% prediction interval = (-42.63862, 60.71971)

f)

No, because 80% is outside sample data

Extrapolation is not trustworthy in linear regression

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