Question

The question asks: what model would you use?  Briefly describe why you would use this model.  What concerns, if any, would you have about the effectiveness of your model? Provide your responses and your justification in the space below.

Attached is the output of linear regression. my first thoughts are that my other choices are higher order regression models. how do I figure this out?

SUMMARY OUTPUT Regression Statistics Multiple R 0.87402183 R Sqae 0.76391416 Adjusted RS 0.7048927 Standard Erro 3.10029472 Observations 21 ANOVA df Significance F 4 497.623143 124.405786 12.94299016.8629E-05 MS Regression Residual Total 16 153.789238 9.61182735 20 651.412381 Coefficients Standard Errot Stat 38.6574921 24.7859709 1.55965212 0.13840106 -13.886419 91.201403313.886419 91.2014033 4.3124406 6.63886864 0.6495746 0.5251835518.386213 9.76133222 -18.386213 9.76133222 0.0186434 0.00821502 -2.2694291 0.03742429 -0.0360585 -0.0012283 -0.0360585-0.0012283 0.0055476 0.00121885 4.5514677 0.00032688-0.0081314 -0.0029637 -0.0081314 0.0029637 2.21286538 2.27693053 0.97186337 0.34558274 2.6140117 7.03974248 2.6140117 7.03974248 P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0% Intercept CO co2 etw cm co Residual Plot etw Residual Plot 5000 0.2 0.3 0.4 0.5 0.2 0.4 0.6 0.8 1.2 10 Co etw co2 Residual Plot cmp Residual Plot 0.4 0.6 0.8 0.2 0.4 0.6 0.8 10 co2 cmp co Line Fit Plot co2 Line Fit Plot ◆ mpg E 20 ◆ mpg Predicted mpg Predicted mpg 0.1 0.2 0.3 0.4 0.5 0.2 0.4 0.6 0.8 1.2 co2 etw Line Fit Plot cmp Line Fit Plot 60 ao 40 E 20 ◆ mpg mpg E -10 0.2 0.4 0.6 0.8 1.2 Predicted mpg Predicted mpg 0.2 0.4 0.6 0.8 1.2 60 etw cmp Normal Probability Plot 20 40 80 100 120 Sample Percentile

Answer 1

Answer

Using the data table given in the question, the p value corresponding to independent variable co and cmp are 0.5252 and 0.3456, which are insignificant at 0.05 level of significance because these p values are greater than 0.05

P values corresponding to independent variable co2 and etw are 0.0374 and 0.0003, which are significant because these p values are less than 0.05 level of significance

So, we will include only co2 and etw independent variables in the final model and will exclude co and cmp independent variables.

Overall F statistics is also significant at 0.05 level of significant.

Therefore, final model is

y = 38.657 -0.0186*(co2) -0.0056(etw)