4. Given two alternatives A and B; Assuming that alternatives are Data replaced at the end of the...
QUESTION 6 Data for two mutually exclusive alternatives are given below. Alternatives B $4,000 $800 А Initial Cost $5,000 Annual Benefits (beginning at end of $1,500 year 1) Annual Costs (beginning at end of year $500 1) Salvage Value $500 Useful Life (years) 5 $200 $0 10 Compute the net present worth for each alternative and choose the better alternative. MARR = 8%
The cash flows for three different alternatives are given below. Assume that alternatives are replaced at the end of their useful lives. The MARR is 8%. Data P Q R Initial cost $5000 $1000 $2500 Benefits per year $650 0 $350 Salvage value $5000 $1760 $2500 Life 20 years 5 years 10 years The incremental ROR between alternatives “Q” and “R” is? withouut using excal
1) Consider these two machines (alternatives): (12 Points) B A $5000 $1750 $700 $8200 $1850 $500 First Cost Uniform annual benefit Salvage Value Useful Life, in Years 4 If the MARR (minimum attractive rate of return) -7 % , which alternative should be selected? Use the Present worth Analysis method. 1) Consider these two machines (alternatives): (12 Points) B A $5000 $1750 $700 $8200 $1850 $500 First Cost Uniform annual benefit Salvage Value Useful Life, in Years 4 If the...
Need cash flow diagram 04) Three mutually exclusive alternative are being considered Initial Cost Benefit at the end of the first Year Uniform Annual Benefits at end of subsequent years Useful Life in years $500 $200 $100 $400 $200 $125 $300 $200 $100 At the end of its useful life, an alternative is not replaced. If MARR is 10%, which alternatives should be selected? a) Based on the payback period? b) Based on benefit-cost ratio analysis c) Benefit/Costs Analysis using...
Three mutually exclusive alternatives are being considered: Initial cost Benefit at end of the first $500 $400 $300 200 200 200 year Uniform benefit at end of 100 125 100 subsequent years Useful life, in years 4 At the end of its useful life, an alternative is not replaced. If the MARR is 10%, which alternative should be selected (a) Based on the payback period? (b) Based on benefit-cost ratio analysis?
9-54 Three mutually exclusive alternatives are beine A considered: $500 $400 $300 200 100 Initial cost Benefit at end of the first 200 200 year Uniform benefit at end of 100 125 subsequent years Useful life, in years 4 At the end of its useful life, an alternative is not replaced. If the MARR is 10%, which alternative should be selected (a) Based on the payback period? (b) Based on benefit-cost ratio analysis? 9-54 Three mutually exclusive alternatives are beine...
The formula is NPW but I'm a little confused on how it is implemented. Write step by step, please. Don't use Excell please Given 2 alternatives: A B First Cost 4,000 6,000 500 1,000 2,200 Annual Cost Annual Bene fit 2,000 Life 5 10 1,000 Salvage 3,000 If i 10%, find the better alternative computing NPW of both alternatives Assume alternative A is replaced at the end of its useful life. Solution: gr pW
Please don't use excel and show all work. Consider two alternatives: B A $300 $500 $75 Cost $75 Uniform annual benefit X Infinity Useful life, in years Assume that Alt. B is not replaced at the end of its useful life. If the MARR is 10%, what must be the useful life of B to make Alternatives A and B equally desirable?
8 pts Question 11 Consider the following two mutually exclusive alternatives: $ 20,000 Uniform amul benefit Useful life in years Alternative B may be replaced with an identical item every 20 years at the same $28,000 cost and will have the same $2.750 uniform annual benefit. Ata 7% interest rate, use the annual cash flow analysis method to find which alternative should be selected. ཀྱིས 12pt Paragraph Consider the following two mutually exclusive alternatives: $ 20,000 2.000 $28.000 2.750 Uniform...
Three alternatives Machines have the following cost data associated with them. Machine Y Machine Z 10 Data Useful Life, Years First Cost Annual Benefit Annual M&O Costs Annual additional M&O cost in Gradient Salvage Value Loan Payment Machine X 10 $1,325,000 $265,000 $95,000 $2,300 $1,980,000 $589,000 $97,000 $2,100 $1,650,000 $435,000 $91,000 $1,980 $145,000 $150,946 $205,000 $225,565 $178,000 $187,971 The loan payments are calculated using an interest rate of 10%, a life equal to the life of the machine, and a...