Question

Explain using theory, why does the simulation result is shown as followed

Wheatstone Bridge + inverting amplifier

Rf R1 R3 Rs VO R2 RxSimulation condition1. Parametric simulation (Vo vs R,) . Sweep AR (0-50(2)R3 R4 20k 20k ND 0 OU V1 R1 2 ND R5 R6 R7 1k uA741 GND 20k Rsweep) 20k R2 100k PARAMETERS5.00v 4.98 4.96 4.94V 35 40 45 50 15 20 25 30 10

Rf R1 R3 Rs VO R2 Rx
Simulation condition
1. Parametric simulation (Vo vs R,) . Sweep AR (0-50(2)
R3 R4 20k 20k ND 0 OU V1 R1 2 ND R5 R6 R7 1k uA741 GND 20k Rsweep) 20k R2 100k PARAMETERS
5.00v 4.98 4.96 4.94V 35 40 45 50 15 20 25 30 10
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Answer #1

21 by 20Kt 2ok LO K loR lol vQ. 20k

  • output voltage is a linear function varying with swipe resistance with negative slope.
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