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Compare the K Would these sulfides precipitate under the conditions given above? Explain. 2. calc...
Please help me! Thank you so much! 2. Give chemical equations for the following: a. Precipitating the silver ion b...
Please help me! Thank you so much!
2. Give chemical equations for the following: a. Precipitating the silver ion by adding hydrochloric acid b. Precipitating the copper ion by adding sodium sulfide c. Dissolving the copper sulfide in concentrated nitric acid to precipitate sulfur. (The orange gas that you saw is NO, product, and sulfur precipitate can be shown as "S") d. Confirming the identity of the ion as copper by adding potassium ferricyanide. (Pote is only a spectator ion...
Why wouldnt a weak base, such as NH3, work just as well as KOH in (1)?...
Why wouldnt a weak base, such as NH3, work just as well as KOH
in (1)?
2.2 Is the question I have. I figured out
2.1 already.
Below is relevant info. Thanks!
2. (1) Describe how adding a solution of KOH to the original sulfide precipitate results in the separa- tion of Sn4+ ion from the other Group W cations. (2) Why wouldn't a weak base, such as aque- ous NH3, work just as well as aqueous KOH in (1)?...
31). 31) To convert a given number of moles into the number of atoms, one would...
31). 31) To convert a given number of moles into the number of atoms, one would multiply by which of the following factors? A) 1.66 x 10-24 atoms/1 mol B) 1 mol/6.022 x 1023 atoms C) molar mass D) 6.022 x 1023 atoms/1 mol E) 1 mol/1.66 x 10-24 atoms 32) 32) How many atoms of sulfur are present in a 155 g sample of sulfur? [Molar mass: S, 32.06 g/mol] A) 6.02 x 1023 atoms B) 2.91 x 1023...
1. A solution contains 8.68×10-3 M sodium hydroxide and 6.04×10-3 M ammonium sulfide. Solid manganese(II) nitrate...
1. A solution contains 8.68×10-3 M sodium hydroxide and 6.04×10-3 M ammonium sulfide. Solid manganese(II) nitrate is added slowly to this mixture. A. What is the formula of the substance that precipitates first? formula = B. What is the concentration of manganese(II) ion when this precipitation first begins? [Mn2+] = M 2. A solution contains 5.04×10-3 M magnesium nitrate and 1.31×10-2 M nickel(II) acetate. Solid sodium hydroxide is added slowly to this mixture. A. What is the formula of...
Please help with solving Question 1 (A-C) Thank you! Unless otherwise specified in the problem, you...
Please help with solving Question 1 (A-C) Thank you!
Unless otherwise specified in the problem, you may assume that all solutions are at 25°C. 1. 50.0 mL of a pH 6.00 carbonic acid buffer is titrated with 0.2857 M NaOH, requiring 17.47 mL to reach the second equivalence point. a. Calculate the molarity of carbonic acid and bicarbonate in the original buffer. Carbonic acid: Bicarbonate: b. Calculate the pH of the solution after a total of 100.0 mL of 0.2857...
Please help me! Thank you so much!
2. Give chemical equations for the following: a. Precipitating the silver ion by adding hydrochloric acid b. Precipitating the copper ion by adding sodium sulfide c. Dissolving the copper sulfide in concentrated nitric acid to precipitate sulfur. (The orange gas that you saw is NO, product, and sulfur precipitate can be shown as "S") d. Confirming the identity of the ion as copper by adding potassium ferricyanide. (Pote is only a spectator ion...
Why wouldnt a weak base, such as NH3, work just as well as KOH
in (1)?
2.2 Is the question I have. I figured out
2.1 already.
Below is relevant info. Thanks!
2. (1) Describe how adding a solution of KOH to the original sulfide precipitate results in the separa- tion of Sn4+ ion from the other Group W cations. (2) Why wouldn't a weak base, such as aque- ous NH3, work just as well as aqueous KOH in (1)?...
31). 31) To convert a given number of moles into the number of atoms, one would multiply by which of the following factors? A) 1.66 x 10-24 atoms/1 mol B) 1 mol/6.022 x 1023 atoms C) molar mass D) 6.022 x 1023 atoms/1 mol E) 1 mol/1.66 x 10-24 atoms 32) 32) How many atoms of sulfur are present in a 155 g sample of sulfur? [Molar mass: S, 32.06 g/mol] A) 6.02 x 1023 atoms B) 2.91 x 1023...
Please help with solving Question 1 (A-C) Thank you!
Unless otherwise specified in the problem, you may assume that all solutions are at 25°C. 1. 50.0 mL of a pH 6.00 carbonic acid buffer is titrated with 0.2857 M NaOH, requiring 17.47 mL to reach the second equivalence point. a. Calculate the molarity of carbonic acid and bicarbonate in the original buffer. Carbonic acid: Bicarbonate: b. Calculate the pH of the solution after a total of 100.0 mL of 0.2857...
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