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Trial 1 Trial 2 Trial 3 0.5038 O.5086 1. Mass of KHCSH O4 (KHP), g 2. Molar mass of KHCsH404, g/mol 3. Moles of KHC$H404, mol

I need help on part #3, #7, #8, #9

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Answer #1
Calculations Trail 1 trail 2
1. Mass of KHP, g 0.5038 0.5086
2. Molar mass of KHP, g/mol 204.22 204.22
3. Moles of KHP, mol Moles= Mass/ Molar mass 0.00247 0.00249
4. Initial buret reading, mL 23.51 47.1
5. final buret reading, mL 0 23.51
6.volume of NaOH used, mL Final -Initial buret reading 23.51 23.59
7. Moles of NaOH , mol

1mol of NaOH titrates 1 mol of KHP, moles of NaOH = moles of KHP

0.00247 0.00249
8. Molarity of NaOH, mol/L

molarity =moles/ Volume of NaOH in L

1000 mL = 1L

(0.00247)*1000/23.51 = 0.1047 0.1056
9. Average Molarity of NaOH, mol/L ( Molarity of NaOH from Trail 1+ Molarity of NaOH from Trail 2)/2 0.1051
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