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Redo the above problem with additional support settlement of 10mm and 25mm at B and D. E=200 GPa, I = 40×106mm4. Verify the results with RISA-2D.

15kN 5KN Sk.N/m 22/ Redo the above problem with additional support settlement of 10mm and 25mm at B and D. E-200 GPa, 1 = 40x


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15kN 5KN Sk.N/m 22/ Redo the above problem with additional support settlement of 10mm and 25mm at B and D. E-200 GPa, 1 = 40x106mm. Verify the results with RISA-2D. 3.
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Answer #1

Given 3m--オ 2_T SKN/m Re E= 200 GPa , L-40乂106mm 10 mm solution - O ixed End moments ー -9.375 KN·m --SxS2 2. KN·m ニナ10.42 123 EL Lt 40 00 (modiied slo pe defleation equotion due to Smple suppot A) Settlement is in leftside ω¡thorspect bac i s cons iuilibnum equations Doint8 to.oo 4 š EL-g.375 =0 2.3S EL ов +0.8 ELoc +0.0029 EL-9375:0 0 /2.35 Joint C oividing equation and3.41 ELOc +(0,002 73X8000) t 3.828 0 ,, Put this in eg uation we get 2.3S EL19 8 49 Put these Values and fnd fnal moments 4 F1.8 7: S3 mco = Anal moments s (Sagging) c 3453 . (Hogging)S Suppoot Reactions- IS S m Srn RA RC, RC2 A B 21S4 -S,38S 4 RCI 22-62나 KN RBa - IS-22, 624 = -7. С 24 KN 2- CD RC-25-4 , 534suppot Reactions - RA = S. 385 KN RB -13 KN Rc 43,03 KN 584 KA Free moments ISYS = 18.75 KN m 2 SXS2 1S.G2S S4-S8 18-7S 15 G2

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